Php Mysql Group by similer 2字段？

表结构：

当前结果

$query4 = "SELECT bill.agent_id, bill.date, SUM(bill.amount + bill.cheque) AS total, bill_agents.id,bill_agents.name ".
              "FROM bill, bill_agents ".
              "WHERE bill.agent_id = bill_agents.id AND YEAR(date)  = YEAR(CURDATE()) AND MONTH(date) = MONTH(CURDATE()) ". 
              "GROUP BY bill.date , bill.agent_id  ".
              "ORDER BY bill.date ASC";

但我想得到如下结果

+---------+----+----+----+-----+----+
|         |  1 |  2 |  3 |   4 |  5 |
+---------+----+----+----+-----+----+
| Agent 1 | 35 |  0 |  0 |   0 |  0 |
| Agent 2 |  0 | 10 |  0 |   0 |  0 |
| Agent 1 |  0 |  0 | 12 |   0 |  0 |
| Agent 3 |  0 |  0 |  0 | 100 |  0 |
| Agent 6 |  0 |  0 |  0 |   9 |  0 |
| Agent 2 |  0 |  0 |  0 |   9 | 14 |
+---------+----+----+----+-----+----+

Php代码

+---------+----+----+----+-----+----+
|         |  1 |  2 |  3 |   4 |  5 |
+---------+----+----+----+-----+----+
| Agent 1 | 35 |  0 | 12 |   0 |  0 |
| Agent 2 |  0 | 10 |  0 |   0 | 14 |
| Agent 3 |  0 |  0 |  0 | 100 |  0 |
| Agent 6 |  0 |  0 |  0 |   9 |  0 |
+---------+----+----+----+-----+----+

问题在组中，由部分：

请尝试以下查询：

<?php 

    $query4 = "SELECT bill.agent_id, bill.date, SUM(bill.amount + bill.cheque) AS total, bill_agents.id,bill_agents.name ".
              "FROM bill, bill_agents ".
              "WHERE bill.agent_id = bill_agents.id AND YEAR(date)  = YEAR(CURDATE()) AND MONTH(date) = MONTH(CURDATE()) ". 
              "GROUP BY bill.date , bill.agent_id  ".
              "ORDER BY bill.date ASC";

    $result4 = mysql_query($query4) or die('Error, query failed1'); 
    if  (mysql_num_rows($result4)>0){
    mysql_data_seek($result4, 0);   

?>
  <?php while($row4 = mysql_fetch_array($result4, MYSQL_ASSOC)){?>
  <?php $date =    $row4['date'];

    $var = $date;
    $date = date("d-m-Y", strtotime($var) );
    $date=substr($date, 0, -8); 

    echo $date;

    ?>
  <tr>
    <td><?php echo $row4['name']; ?></td>

    <td><?php if ($date == 01) echo $row4['total']; ?></td>
    <td><?php if ($date == 02) echo $row4['total']; ?></td>
    <td><?php if ($date == 03) echo $row4['total']; ?></td>
    <td><?php if ($date == 04) echo $row4['total']; ?></td>
    <td><?php if ($date == 05) echo $row4['total']; ?></td>
    <td><?php if ($date == 06) echo $row4['total']; ?></td>
    <td><?php if ($date == 07) echo $row4['total']; ?></td>
    <td><?php if ($date == 08) echo $row4['total']; ?></td>
    <td><?php if ($date == 09) echo $row4['total']; ?></td>
    <td><?php if ($date == 10) echo $row4['total']; ?></td>

---

两个查询都会生成相同的结果

$query4 = "SELECT bill.agent_id, bill.date, SUM(bill.amount + bill.cheque) AS total,
bill_agents.id,bill_agents.name ".
"FROM bill, bill_agents ".
"WHERE bill.agent_id = bill_agents.id AND YEAR(date)  = YEAR(CURDATE()) 
AND MONTH(date) = MONTH(CURDATE()) ". 
"GROUP BY DATE(bill.date) , bill.agent_id ".
"ORDER BY bill.date ASC";