Php 选择上周中的行进行计数

我有一个sql区块，用于计算每个名称在数据表中出现的次数：

$picksql = mysql_query("
    (SELECT DISTINCT guy1 AS player FROM data_match) UNION
    (SELECT DISTINCT guy2 AS player FROM data_match) UNION
    (SELECT DISTINCT guy3 AS player  FROM data_match)UNION
    (SELECT DISTINCT guy4 AS player  FROM data_match)UNION
    (SELECT DISTINCT guy5 AS player FROM data_match) UNION
    (SELECT DISTINCT guy6 AS player  FROM data_match)
    ORDER BY player;");

$picksql2 = mysql_query("SELECT player,count(distinct match_id) as numberofgames FROM data_match  t1 JOIN (
    (SELECT DISTINCT guy1 AS player FROM data_match) UNION 
    (SELECT DISTINCT guy2 AS player FROM data_match) UNION 
    (SELECT DISTINCT guy3 AS player  FROM data_match) UNION
    (SELECT DISTINCT guy4 AS player  FROM data_match)UNION
    (SELECT DISTINCT guy5 AS player FROM data_match) UNION
    (SELECT DISTINCT guy6 AS player  FROM data_match)
    ORDER BY player) t2 
    WHERE t2.player=t1.guy1 OR t2.player=t1.guy2 OR t2.player=t1.guy3 OR t2.player=t1.guy4 OR t2.player=t1.guy5 OR t2.player=t1.guy6  GROUP by t2.player");

问题是，我只想选择过去一周的比赛。我应该在哪里输入类似于：

WHERE date >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY
AND date < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY

其中date>=curdate（）-每周间隔DAYOFWEEK（curdate（））+6天
和日期

---

为了使其仅从过去2周中选择？非常感谢，我很感激D

。。。或者t2.player=t1.guy6和date>=curdate（）-INTERVAL DAYOFWEEK（curdate（））+6天和date

似乎改变了数字，但只改变了一点点。当我使用查询

SELECT*FROM data\u smite\u match2 WHERE date>=curdate（）-INTERVAL DAYOFWEEK（curdate（））+6天和date