Php while循环中有什么问题吗？

我有一张商店积分表

和订单表

我想要的输出与此类似，但基于

存储信用订单日期和时间

和

存储订单日期和时间

：

到目前为止我已经尝试过的代码：

<?php
$table = '';
$queryToGetStoreCredit = "SELECT * FROM store_credits_orders WHERE SCO_CustEmailAdd = '".$_SESSION["Customer"]["email"]."'";
$validate->Query($queryToGetStoreCredit);
if ($validate->NumRows() >= 1) {
    while ($rows_sco = $validate->FetchAllDatas()) {
        $used = $i = 0;
        $table .= '<tr>';
        $table .= '<td>'.$rows_sco["SCO_OrderCode"].'</td>';
        $table .= '<td>--</td>';
        $table .= '<td>'.$rows_sco["SCO_OrderDate"].'</td>';
        $table .= '<td>--</td>';
        $table .= '<td>'.$rows_sco["SCO_Purchase_Amount"].'</td>';
        $table .= '<td>'.$rows_sco["SCO_Credit_Alloted"].'</td>';
        $table .= '<td>'.$used.'</td>';
        $table .= '<td>'.( $rows_sco["SCO_Credit_Alloted"] - $used ).'</td>';
        $table .= '</tr>';

        $validate2 = new Validation();
        $queryToGetOrder = "SELECT * FROM orders WHERE CustEmailAdd = '".$rows_sco["SCO_CustEmailAdd"]."'";
        $validate2->Query($queryToGetOrder);
        while ($row = $validate2->FetchAllDatas()) {
            $table .= '<tr>';
            $table .= '<td>--</td>';
            $table .= '<td>'.$row["OrderCode"].'</td>';
            $table .= '<td>--</td>';
            $table .= '<td>'.$row["OrderDate"].'</td>';
            $table .= '<td>--</td>';
            $table .= '<td>--</td>';
            $table .= '<td>'.$row["AppliedCredits"].'</td>';
            $table .= '<td>'.($rows_sco["SCO_Credit_Alloted"] - $row["AppliedCredits"]).'</td>';
            $table .= '</tr>';
        }
    }
}
?>

我想要实现的是，无论何时购买门店积分，信息都将插入

门店积分订单
表中。现在，当同一个用户来下订单并兑换store_信用（小于等于，他在他的帐户中有），除了在orders表中插入之外，数据库中不会有任何更新

但是当用户登录时，他应该能够看到他何时购买了商店积分和/或何时兑换了商店积分。所有这些事件都应该按最先发生的事件排序，无论是购买还是赎回。
我和@user3514160谈过，我很清楚他想要什么。基本上，数据被正确插入。他唯一想要的就是以正确的方式显示数据

您的查询应如下所示

(SELECT
  SCO_Id,
  SCO_OrderCode,
  SCO_CustEmailAdd,
  SCO_Purchase_Amount,
  SCO_Credit_Alloted,
  SCO_OrderDate,
  SCO_OrderIP,
  null AS OrderId,
  null AS OrderCode,
  null AS CustEmailAdd,
  null AS AppliedCredits,
  null AS OrderDate,
  'store_credits_orders' AS tableName
FROM `store_credits_orders` AS credits_orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
UNION
(SELECT
  OrderId,
  OrderCode,
  CustEmailAdd,
  AppliedCredits,
  OrderDate
  null AS SCO_Id,
  null AS SCO_OrderCode,
  null AS SCO_CustEmailAdd,
  null AS SCO_Purchase_Amount,
  null AS SCO_Credit_Alloted,
  OrderDate AS SCO_OrderDate,
  null AS SCO_OrderIP,
  'store_orders' AS tableName
FROM `store_orders` AS orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
ORDER BY `SCO_OrderDate` ASC

这是在一个结果中获取所有行所必需的。我们通过以下方式来实现这一点

UNION需要两个表具有相同数量的同名列。这就是为什么我们添加列名为
null的空列

和带有查询的PHP

<?php
$table = '<table>';

// Query to get all rows from both tables
$queryToGetStoreCredit = 
"(SELECT
  SCO_Id,
  SCO_OrderCode,
  SCO_CustEmailAdd,
  SCO_Purchase_Amount,
  SCO_Credit_Alloted,
  SCO_OrderDate,
  SCO_OrderIP,
  null AS OrderId,
  null AS OrderCode,
  null AS CustEmailAdd,
  null AS AppliedCredits,
  null AS OrderDate,
  'store_credits_orders' AS tableName
FROM `store_credits_orders` AS credits_orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
UNION
(SELECT
  OrderId,
  OrderCode,
  CustEmailAdd,
  AppliedCredits,
  OrderDate
  null AS SCO_Id,
  null AS SCO_OrderCode,
  null AS SCO_CustEmailAdd,
  null AS SCO_Purchase_Amount,
  null AS SCO_Credit_Alloted,
  OrderDate AS SCO_OrderDate,
  null AS SCO_OrderIP,
  'store_orders' AS tableName
FROM `store_orders` AS orders WHERE `SCO_CustEmailAdd` = '".$_SESSION["Customer"]["email"]."')
ORDER BY `SCO_OrderDate` ASC";

$validate->Query($queryToGetStoreCredit);
if ($validate->NumRows() >= 1) {
    // Starting balance. This could be some other number, for example if viewing some certain period of orders etc.
    $balance = 0;
    while ($row = $validate->FetchAllDatas()) {

        // Add to balance
        if($row['tableName'] == 'store_credits_orders' && (int)$row['SCO_Credit_Alloted'] > 0){
          $balance += (int)$row['SCO_Credit_Alloted']
        }
        // Remove from balance
        else if($row['tableName'] == 'store_orders' && (int)$row['AppliedCredits'] > 0){
          $balance -= (int)$row['AppliedCredits'];
        }

        $table .= '<tr>';
        $table .= '<td>'.$row["SCO_OrderCode"].'</td>';
        $table .= '<td>'.$row["OrderCode"].'</td>';
        $table .= '<td>'.(($row['tableName'] == 'store_credits_orders') ? $row["SCO_OrderDate"] : '').'</td>';
        $table .= '<td>'.$row["OrderDate"].'</td>';
        $table .= '<td>'.$row["SCO_Purchase_Amount"].'</td>';
        $table .= '<td>'.$row["SCO_Credit_Alloted"].'</td>';
        $table .= '<td>'.$row["AppliedCredits"].'</td>';
        $table .= '<td>'.$balance.'</td>';
        $table .= '</tr>';
    }
}

$table .= '</table>';

echo $table;
?>

您的更新查询在哪里？您的问题也有点不清楚？哪个更新查询？还有什么？你问“我需要在兑换和/或购买时更新商店积分。”？我要问的那个问题需要在运行时完成。。。我们不会对此提出任何疑问。@halfer谢谢您的通知，先生。我不知道这一切。我将确保下次不会发生这种情况。最好在sql联合中显式地声明返回的列，而不是使用“*”（返回所有列）。原因是，如果向任一表中添加新列，则查询将失败。此外，您还依赖于两个表中顺序相同的相应列。是的，编辑了我的答案@RyanVincent，依赖相同的列顺序是什么意思？如果我们为第二次查询的最后两列设置null，
SCO\u Credit\u allocated
将获得
OrderDate
的值，这是我们不想要的。目前，所有列名都被保留。