Php 如何获取浏览器（而不是服务器网站）的地理位置

好的，我有这个脚本，它可以工作，但是：

<?php
SESSION_START();
// access_token received from /oauth2/token call
// Assign it the properties of id (optional - id of target HTML element, from URL)
// and 'message' - the feedback message we want the user to see.
if (isset($_GET['wxurl'])) {
    $wxURL = $_GET['wxurl'];
}

if ($wxURL === "autoip") {
    //Get the IP of the location
    $uri = curl_init("http://api.wunderground.com/api/<APIKEY>/geolookup/q/autoip.json");
} else if ($wxURL === "wxcity") {
    if (isset($_GET['city']) && isset($_GET['state'])) {
        $wxCity = $_GET['city'];
        $wxState = $_GET['state'];
    }
    //Get the locations weather data
    $uri = curl_init("http://api.wunderground.com/api/<APIKEY>/conditions/q/" . $wxState . "/" . $wxCity . ".json");
} else if ($wxURL === "freeJSON") {
    //This gets the ACTUAL USERS location NOT that of the server **<--- WELL it's SUPPOSED to get the LOCATION of the user NOT the server**
    $uri = curl_init("http://freegeoip.net/json/");
}

$ch = $uri; // URL of the call
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array("Authorization: Bearer $access_token"));
// execute the api call
$result = curl_exec($ch);

echo $result;

所以，Geolocation.js让我困惑

想法

{
    ip: "11.22.333.444",
    country_code: "US",
    country_name: "United States",
    region_code: "WA",
    region_name: "Washington",
    city: "MT Vernon",
    zip_code: "98273",
    time_zone: "America/Los_Angeles",
    latitude: 47.5614,
    longitude: -123.7705,
    metro_code: 985
}