Php 使用preg_match_all()和结束字符匹配一个字符串中的多个项目
我有以下代码:Php 使用preg_match_all()和结束字符匹配一个字符串中的多个项目,php,regex,pcre,Php,Regex,Pcre,我有以下代码: preg_match_all('/(.*) \((\d+)\) - ([\d\.\d]+)[,?]/U', "E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15", $match); var_dump($string, $match); 并获得以下输出: array(4) { [0]=> array(1) { [0]=>
preg_match_all('/(.*) \((\d+)\) - ([\d\.\d]+)[,?]/U',
"E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15",
$match);
var_dump($string, $match);
并获得以下输出:
array(4) {
[0]=>
array(1) {
[0]=>
string(54) "E-Book What I Didn't Learn At School... (2) - 3525.01,"
}
[1]=>
array(1) {
[0]=>
string(39) "E-Book What I Didn't Learn At School..."
}
[2]=>
array(1) {
[0]=>
string(1) "2"
}
[3]=>
array(1) {
[0]=>
string(7) "3525.01"
}
}
它只匹配一个项目。。。我需要的是从这些字符串中获取所有项。当我在字符串末尾添加“,”符号时,效果很好。但在每个字符串中添加逗号是没有意义的。有什么建议吗?试试这个正则表达式:
(.*?)\s*\((\d+)\)\s*-\s*(\d+\.\d+)(?:,\s*)?
主要的区别是您有*
(贪婪),我将其替换为*?
(非贪婪)。你的第一个“吃”了整个弦(断线除外),然后回溯到只匹配你弦中的一段
演示:
产生:
Array
(
[0] => Array
(
[0] => E-Book What I Didn't Learn At School... (2) - 3525.01,
[1] => E-Book What I Didn't Learn At School...
[2] => 2
[3] => 3525.01
)
[1] => Array
(
[0] => FREE Intro DVD/Vid (1) - 0.15
[1] => FREE Intro DVD/Vid
[2] => 1
[3] => 0.15
)
)
但是如何处理逗号呢?看看第二个item@nefo_x使用了
/U
修饰符,默认情况下,该修饰符使量词不贪婪。这就是为什么你不应该使用这个修饰语;它不可避免地造成的混乱超过了任何好处。如果你想要一个量词是非贪婪的,那就添加一个?
@Alan,啊,我认为这与Unicode有关,但我想这是一个小写的u
。谢谢
Array
(
[0] => Array
(
[0] => E-Book What I Didn't Learn At School... (2) - 3525.01,
[1] => E-Book What I Didn't Learn At School...
[2] => 2
[3] => 3525.01
)
[1] => Array
(
[0] => FREE Intro DVD/Vid (1) - 0.15
[1] => FREE Intro DVD/Vid
[2] => 1
[3] => 0.15
)
)