php打印f数组错误

我正在做一个php来推送GCM通知，在此之前我需要从数据库中获取数据并发送到GoogleGCM服务器

代码如下：

mysql_select_db($database_gcm_gcm, $gcm_gcm);
 $result = mysql_query("SELECT id, RegID FROM gcm_user ORDER BY id ASC") or die(mysql_error());

$list_arr = array(array());

for($i=0; ($row = mysql_fetch_array($result)); $i++){
        $list_arr[$i]=$row;
        print_r ($row . '<br>');
     }

print_r($result . '<br>');

?>

但它只显示单词数组和资源id 4

哪一部分我做错了

---

谢谢

您不能打印带有for的查询。你必须使用do-while

请尝试以下代码：

mysql_select_db($database_gcm_gcm, $gcm_gcm);
$result = mysql_query("SELECT id, RegID FROM gcm_user ORDER BY id ASC") or die(mysql_error());
$row = mysql_fetch_array($result);

do{
     echo $row['id'] ." " .$row['RegID'] ."<br />";
} while ($row = mysql_fetch_array($result));

mysql_select_db($database_gcm_gcm, $gcm_gcm);
$result = mysql_query("SELECT id, RegID FROM gcm_user ORDER BY id ASC") or die(mysql_error());
$row = mysql_fetch_array($result);

do{
     echo $row['id'] ." " .$row['RegID'] ."<br />";
} while ($row = mysql_fetch_array($result));

$list_arr = [];

    $resultCount = mysql_num_rows($result); 
    if ($resultCount > 0) 
    {
        while($row = mysql_fetch_array($result))
        {   
            $list_arr[$i] = $row['id'].','.$row['RegID '];

        }
    }