如何使用mysql和php选择多行？

我有两张桌子

广告

A图像

这里的tableadsid和tableadImagesadsId是相同的。在这里，我必须从表ads和adImages中选择所有行，并以json格式显示

我的代码看起来：

$query="SELECT a.*, b.images FROM `ads` AS a INNER JOIN `adImages` AS b ON a.id = b.adsId";

$result=mysql_query($query);
$value = mysql_num_rows($result);
if($value>=1)
{   
     while($row = mysql_fetch_array($result)) 
    {
        $details[] = array(

        'id' => $row['id'], 
        'location' => $row['location'],
        'title'=>$row['title'],
        'mobile' => $row['mobile'],
        'description' => $row['description'],
        'category' => $row['category'],
        'images' =>'http://greenwma.com/dev/uploads/'.$row['images'],
        );
    }
    echo  json_encode($details);
}

其输出json如下所示：

[{"id":"10","location":"9.982852,76.300637","title":"Ggg","mobile":"5555555","description":"Google","category":"BusMedia","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016062319:07:39.jpg{"id":"10","location":"9.982852,76.300637","title":"Ggg","mobile":"5555555","description":"Google","category"BusMedia","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 17:27:05.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:15:16.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:08:50.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:07:39.jpg"}]

这里的问题是，id、位置、标题、手机、描述、类别对同一adsId上的每个图像重复

我需要的是，我必须以这种格式获取json

[{"id":"10","location":"9.982852,76.300637","title":"Ggg","mobile":"5555555","description":"Google ","category":"Bus Media","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:07:39.jpg","http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 17:27:05.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:15:16.jpg","http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:08:50.jpg","http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:07:39.jpg"}]

也就是说，我必须在单个json对象中获得所有用逗号分隔的图像。为此，我应该在上面的代码中做哪些更改

您可以使用CONCAT（）&和子查询在一个查询和较少的循环中完成

SELECT a.*, GROUP_CONCAT(images) images FROM (
SELECT a.*, CONCAT('http://greenwma.com/dev/uploads/', b.images) images
FROM `ads` AS a 
INNER JOIN `adImages` AS b ON a.id = b.adsId 
) tbl
GROUP BY id

您可以将CONCAT（）与子查询一起使用，在一个查询和较少的循环中完成此操作

SELECT a.*, GROUP_CONCAT(images) images FROM (
SELECT a.*, CONCAT('http://greenwma.com/dev/uploads/', b.images) images
FROM `ads` AS a 
INNER JOIN `adImages` AS b ON a.id = b.adsId 
) tbl
GROUP BY id

---

为什么您仍在使用mysql_*函数？你知道他们不赞成吧？同意。无论您出于什么原因使用

mysql\u xxx（）

函数，您都需要停下来学习如何使用PDO库。

mysl_xx（）

函数已经从最新的PHP版本中删除，并且在那之前的十多年中一直被认为是不好的做法。你的代码严重落后于时代。为什么你还在使用mysql_*函数？你知道他们不赞成吧？同意。无论您出于什么原因使用

mysql\u xxx（）

函数，您都需要停下来学习如何使用PDO库。

mysl_xx（）

函数已经从最新的PHP版本中删除，并且在那之前的十多年中一直被认为是不好的做法。你的代码严重落后于时代。