Php 为什么没有设置$\u文件

Php 为什么没有设置$\u文件,php,html,forms,file,file-upload,Php,Html,Forms,File,File Upload,这是我的html表单的一个片段 <form class="form-horizontal" role="form" method="post" enctype="multipart/form-data"> <div class="form-group"> <label for="profilepictureinput">Profile Picture</label> <input type="file"

这是我的html表单的一个片段

<form class="form-horizontal" role="form" method="post" enctype="multipart/form-data">
    <div class="form-group">
        <label for="profilepictureinput">Profile Picture</label>
        <input type="file"
               id="profilepictureinput"
               name="profilepicture">
    </div>
    <button type="submit" class="btn btn-default">Submit</button>
</form>

返回false。这是为什么?

$\u文件更改为
$\u文件

isset($_FILES['profilepicture']) 

如果未提交表单,它将返回
false
。提交后,它将返回
true

,正如Tom Kriek所说,正确的语法是:

$_FILES['profilepicture']

首先,若表单已提交,则需要先与$\u POST核对,然后才能从$\u文件中获取信息。 你应该这样写:

<form class="form-horizontal" role="form" method="post" enctype="multipart/form-data">
    <div class="form-group">
        <label for="profilepictureinput">Profile Picture</label>
        <input type="file" id="profilepictureinput" name="profilepicture">
    </div>
    <button type="submit" class="btn btn-default" name="new-picture">Submit</button>
</form>
"; 退回$out; }
因为它是$\u文件请检查此链接:很抱歉,我使用了$\u文件,但它仍然不起作用。如果是这样的话,发布更多代码以供参考可能会有所帮助。请打印完整的$\u文件数组。检查其中的实际内容。
<form class="form-horizontal" role="form" method="post" enctype="multipart/form-data">
    <div class="form-group">
        <label for="profilepictureinput">Profile Picture</label>
        <input type="file" id="profilepictureinput" name="profilepicture">
    </div>
    <button type="submit" class="btn btn-default" name="new-picture">Submit</button>
</form>
<button type="submit" class="btn btn-default" name="new-picture">Submit</button>
<?php
//$newImageSubmitted is TRUE if form was submitted, otherwise FALSE
$newImageSubmitted = isset( $_POST['new-image'] );

if ( $newImageSubmitted ) {
    //this code runs if form was submitted
    $output = upload();
} else {
    //this runs if form was NOT submitted
    $output = include_once "views/upload-form.php";
}
return $output;

function upload(){
    $out = "<pre>";
    $out .=print_r($_FILES, true);
    $out .= "</pre>";
    return $out;
}