Php 在Laravel中注册期间如何填充2个表？

我想在注册后给用户免费押金。因此我想填写“押金”表和“用户”表。我在下面试过了，但我发现了错误

protected function create(array $data)
    {
        $basic = BasicSetting::first();
        $status = $basic->verify_status == 1 ? '0' : '1';
        $image25 = 'user-default.png';
        if ($basic->reference_id == $data['reference']){
            $user = User::create([
                'name' => $data['name'],
                'email' => $data['email'],

                'under_reference' => $data['reference'],
                'password' => bcrypt($data['password']),
                'verifyToken' => Str::random(40),
                'reference' => Str::random(12),
                'status' => $status,
                'image' => $image25
            ]);
            $Deposit = Deposit::create([
                'deposit_number' => date('ymd').Str::random(6).rand(11,99),
              'plan_id' => $data['planid'],
              'percent' => $data['percent'],
              'time' => $data['time'],
              'compound_id' => $data['comp'],
              'status' = $status
]);

您有一个输入错误：

'status' = $status

应该是

'status' => $status

在

---

你犯了什么错误？你有什么问题？？向我们显示这两个表的db模式错误是什么？@FelippeDuarte分析错误：语法错误，意外的“=”，预期的“]'使用

status=>$status

而不是

status=$status

中的

Deposit

模型。

$Deposit = Deposit::create([
    'deposit_number' => date('ymd').Str::random(6).rand(11,99),
    'plan_id' => $data['planid'],
    'percent' => $data['percent'],
    'time' => $data['time'],
    'compound_id' => $data['comp'],
    'status' = $status     // <------------
]);

if ($basic->reference_id == $data['reference']){
    \DB::transaction(function() use($data) {
        $basic = BasicSetting::first();
        $status = $basic->verify_status == 1 ? '0' : '1';
        $image25 = 'user-default.png';
        $user = User::create([ .... ]);
        $Deposit = Deposit::create([...]);
    });
}