Php 试图编写将阿拉伯语数据插入mysql的代码_Php_Mysql

Php 试图编写将阿拉伯语数据插入mysql的代码

php mysql

Php 试图编写将阿拉伯语数据插入mysql的代码,php,mysql,Php,Mysql,我有以下代码，当我在html表单中按下按钮时运行 <!DOCTYPE html> <html> <head> <?php $timestamp = date("YmdHis"); ?> <link rel="stylesheet" type="text/css" href="style.css"?v=<?php echo time(); ?>"> <meta http-equiv="Content-Type" cont

我有以下代码，当我在html表单中按下按钮时运行

<!DOCTYPE html>
<html>
<head>
<?php $timestamp = date("YmdHis"); ?>
<link rel="stylesheet" type="text/css" href="style.css"?v=<?php echo time(); ?>">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <title>Data Entry</title>
</head>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "";

// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 
$sql->set_charset('utf8');
// Create database
$sql = "CREATE DATABASE IF NOT EXISTS mortgagedb";
if ($conn->query($sql) === TRUE) {
    echo "Database created successfully";
} else {
    echo "Error creating database: " . $conn->error;
}


$sql = "CREATE TABLE IF NOT EXISTS mortgagedb . clientstest (
reg_date TIMESTAMP,
client_code INT(6) UNSIGNED PRIMARY KEY,
project_code INT(6) UNSIGNED NOT NULL,
client_name VARCHAR(255) NOT NULL,
client_id INT(14) NOT NULL,
client_id_expiry VARCHAR(7) NOT NULL,
client_address VARCHAR(255) NOT NULL,
client_profession VARCHAR(255) NOT NULL,
client_phone INT(12) NOT NULL,
income INT(6) NOT NULL,
guarantor_name VARCHAR(255) NOT NULL,
guarantor_id VARCHAR(14) NOT NULL,
guarantor_id_expiry VARCHAR(7) NOT NULL,
guarantor_address VARCHAR(255) NOT NULL,
guarantor_relation VARCHAR(255) NOT NULL,
unit_no VARCHAR(255) NOT NULL,
floor_no VARCHAR(255) NOT NULL,
bulding_no VARCHAR(255) NOT NULL,
location VARCHAR(255) NOT NULL,
project VARCHAR(255) NOT NULL,
city VARCHAR(255) NOT NULL,
governorate VARCHAR(255) NOT NULL,
area VARCHAR(255) NOT NULL,
unit_value INT(7) NOT NULL,
previous_payment INT(7) NOT NULL,
loan_maturity INT(2) NOT NULL,
mortgage_rate INT(2) NOT NULL,
annual_rate_wage INT(2) NOT NULL,
max_pay_inc INT(2) NOT NULL,
prog_max_inc INT(7) NOT NULL,
prog_min_inc INT(7) NOT NULL,
prog_max_sub INT(7) NOT NULL,
prog_min_sub INT(7) NOT NULL,
payment_graduation INT(2) NOT NULL,
iscore VARCHAR(255) NOT NULL,
documents VARCHAR(255) NOT NULL,
condition1 VARCHAR(255) NOT NULL,
condition2 VARCHAR(255) NOT NULL,
condition3 VARCHAR(255) NOT NULL,
condition4 VARCHAR(255) NOT NULL,
condition5 VARCHAR(255) NOT NULL,
condition6 VARCHAR(255) NOT NULL,
condition7 VARCHAR(255) NOT NULL,
condition8 VARCHAR(255) NOT NULL,
condition9 VARCHAR(255) NOT NULL,
condition10 VARCHAR(255) NOT NULL,
condition11 VARCHAR(255) NOT NULL,
condition12 VARCHAR(255) NOT NULL,
condition13 VARCHAR(255) NOT NULL,
condition14 VARCHAR(255) NOT NULL,
attachment1 VARCHAR(255) NOT NULL,
attachment2 VARCHAR(255) NOT NULL,
attachment3 VARCHAR(255) NOT NULL,
attachment4 VARCHAR(255) NOT NULL,
attachment5 VARCHAR(255) NOT NULL,
attachment6 VARCHAR(255) NOT NULL
)";
if ($conn->query($sql) === TRUE) {
    echo "Table clientstest created successfully";
} else {
    echo "Error creating table: " . $conn->error;
}
$sql = "INSERT INTO mortgagedb . clientstest (client_code, project_code, client_name, client_id, client_id_expiry, client_address, client_profession, client_phone, income, guarantor_name, guarantor_id, guarantor_id_expiry, guarantor_address, guarantor_relation, unit_no, floor_no, bulding_no, location, project, city, governorate, area, unit_value, previous_payment, loan_maturity, mortgage_rate, annual_rate_wage, max_pay_inc, prog_max_inc, prog_min_inc, prog_max_sub, prog_min_sub, payment_graduation, iscore, documents, condition1, condition2, condition3, condition4, condition5, condition6, condition7, condition8, condition9, condition10, condition11, condition12, condition13, condition14, attachment1, attachment2, attachment3, attachment4, attachment5, attachment6)
VALUES ('$_POST[ccode]', '$_POST[pcode]', '$_POST[cname]', '$_POST[cid]', '$_POST[ciddate]', '$_POST[caddress]', '$_POST[cjob]', '$_POST[cphone]', '$_POST[inc]', '$_POST[gname]', '$_POST[gid]', '$_POST[giddate]', '$_POST[gaddress]', '$_POST[grel]', '$_POST[un]', '$_POST[floor]', '$_POST[bn]', '$_POST[lctn]', '$_POST[pro]', '$_POST[city]', '$_POST[gov]', '$_POST[area]', '$_POST[unitv]', '$_POST[pp]', '$_POST[lm]', '$_POST[mr]', '$_POST[row]', '$_POST[paytoinc]', '$_POST[maxinc]', '$_POST[mininc]', '$_POST[maxsub]', '$_POST[minsub]', '$_POST[pgr]', '$_POST[iscore]', '$_POST[docs]', '$_POST[con1]', '$_POST[con2]', '$_POST[con3]', '$_POST[con4]', '$_POST[con5]', '$_POST[con6]', '$_POST[con7]', '$_POST[con8]', '$_POST[con9]', '$_POST[con10]', '$_POST[con11]', '$_POST[con12]', '$_POST[con13]', '$_POST[con14]', '$_POST[att1]', '$_POST[att2]', '$_POST[att3]', '$_POST[att4]', '$_POST[att5]', '$_POST[att6]' )";
if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
</body>
</html>


您有$sql->set_字符集（'utf8'）。不过<代码>$sql
仅在下一行定义
尝试将其更改为$conn
 您的错误来自以下行：
$sql->set_charset('utf8');

基本上是正确的，但您根本没有定义$sql
。您需要在连接对象上使用set\u charset

因此，不要编写代码，而是编写：
$conn->set_charset('utf8');

是否确实要在每次运行脚本时创建一个新表？ôo顺便说一句，你在你的新mysqli
中缺少了db\u name
作为参考：$sql->set\u charset@Twinfriends我只希望在数据库不存在的情况下创建数据库，因为这个项目将放在一个我根本无法控制的服务器中all@AbdalrahmanMokhlesAslan所以如果你想让它被创造出来，您应该将其放入IF
语句中。现在，每次运行脚本时，它都会创建一个新表（在第一次出现错误后，因为表存在并且可以执行查询）。@Twinfriends我想这就是为什么我使用Creat IF NOT exists语句的原因，到目前为止，它与我的工作很好：3