MySQL&；PHP foreach中的行总和

我试图得到一行训练的总和，然后按总和对所有行进行排序，以得到团队的位置，并以正确的顺序列出。我现在有点迷失在自己的逻辑中，试图弄明白这一点。我理解MYSQL的sum函数，但似乎不知道如何使用它来帮助我解决这个问题

比如说：

以下是我当前的表架构：

CREATE TABLE workouts
(
team_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
username VarChar(255) NOT NULL,
team_name VarChar(50) NOT NULL,
week1 INT NOT NULL,
week2 INT NOT NULL,
week3 INT NOT NULL,
week4 INT NOT NULL,
week5 INT NOT NULL,
week6 INT NOT NULL,
week7 INT NOT NULL,
week8 INT NOT NULL,
week9 INT NOT NULL,
week10 INT NOT NULL,
week11 INT NOT NULL,
week12 INT NOT NULL
) engine=innodb;

这是我迄今为止的展示：

<?php 
$count = 0;
$statement = $db->query('SELECT * FROM workouts');
foreach($statement as $row):
?>
<tr>
<td><?php $count++; ?></td>
<td><?php $row['team_name']; ?></td>
<td><?php $row['week1']; ?></td>
<td><?php $row['week2']; ?></td>
<td><?php $row['week3']; ?></td>
<td><?php $row['week4']; ?></td>
<td><?php $row['week5']; ?></td>
<td><?php $row['week6']; ?></td>
<td><?php $row['week7']; ?></td>
<td><?php $row['week8']; ?></td>
<td><?php $row['week9']; ?></td>
<td><?php $row['week10']; ?></td>
<td><?php $row['week11']; ?></td>
<td><?php $row['week12']; ?></td>
<td><?php  ?></td>
</tr>
<?php endforeach; ?>

---

我会将此作为SQL的一部分，而不是PHP。与其使用

Sum（）

（设计用于将整个分组序列中的一列相加），不如将这些列相加，并将它们指定为别名“Total”，如下所示：

SELECT week1 + week2 + week3 + weekN Total FROM workouts ORDER BY Total 

<?php 

  $count = 0;
  $statement = $db->query('
    SELECT *, week1 + week2 + week3 + week4 + week5 + week6 + week7 + week8 + week9 + week10 + week11 + week12 AS Total
    FROM workouts
    ORDER BY Total
  ');
  foreach ($statement as $row):
?>
<tr>
<td><?php echo $count++; ?></td>
<td><?php echo $row['team_name']; ?></td>
<td><?php echo $row['week1']; ?></td>
<td><?php echo $row['week2']; ?></td>
<td><?php echo $row['week3']; ?></td>
<td><?php echo $row['week4']; ?></td>
<td><?php echo $row['week5']; ?></td>
<td><?php echo $row['week6']; ?></td>
<td><?php echo $row['week7']; ?></td>
<td><?php echo $row['week8']; ?></td>
<td><?php echo $row['week9']; ?></td>
<td><?php echo $row['week10']; ?></td>
<td><?php echo $row['week11']; ?></td>
<td><?php echo $row['week12']; ?></td>
<td><?php echo $row['Total']; ?></td>
</tr>
<?php endforeach; ?>

---

根据你已经总结的行，最简单的答案是：

<?php 
$count = 0;
$statement = $db->query('SELECT * FROM workouts');
foreach($statement as $row):
?>
<tr>
<td><?php echo $count++; ?></td>
<td><?php echo $row['team_name']; ?></td>
<td><?php echo $row['week1']; ?></td>
<td><?php echo $row['week2']; ?></td>
<td><?php echo $row['week3']; ?></td>
<td><?php echo $row['week4']; ?></td>
<td><?php echo $row['week5']; ?></td>
<td><?php echo $row['week6']; ?></td>
<td><?php echo $row['week7']; ?></td>
<td><?php echo $row['week8']; ?></td>
<td><?php echo $row['week9']; ?></td>
<td><?php echo $row['week10']; ?></td>
<td><?php echo $row['week11']; ?></td>
<td><?php echo $row['week12']; ?></td>
<td><?php echo $row['week1'] + $row['week2'] + $row['week3'] + $row['week4'] + $row['week5'] + $row['week6'] + $row['week7'] + $row['week8'] + $row['week9'] + $row['week10'] + $row['week11'] + $row['week12']; ?></td>
</tr>
<?php endforeach; ?>

但是为了使用这个值来控制行的显示顺序，您需要让MySQL为您完成这项工作

你想做的事情是这样的：

SELECT week1 + week2 + week3 + weekN Total FROM workouts ORDER BY Total 

<?php 

  $count = 0;
  $statement = $db->query('
    SELECT *, week1 + week2 + week3 + week4 + week5 + week6 + week7 + week8 + week9 + week10 + week11 + week12 AS Total
    FROM workouts
    ORDER BY Total
  ');
  foreach ($statement as $row):
?>
<tr>
<td><?php echo $count++; ?></td>
<td><?php echo $row['team_name']; ?></td>
<td><?php echo $row['week1']; ?></td>
<td><?php echo $row['week2']; ?></td>
<td><?php echo $row['week3']; ?></td>
<td><?php echo $row['week4']; ?></td>
<td><?php echo $row['week5']; ?></td>
<td><?php echo $row['week6']; ?></td>
<td><?php echo $row['week7']; ?></td>
<td><?php echo $row['week8']; ?></td>
<td><?php echo $row['week9']; ?></td>
<td><?php echo $row['week10']; ?></td>
<td><?php echo $row['week11']; ?></td>
<td><?php echo $row['week12']; ?></td>
<td><?php echo $row['Total']; ?></td>
</tr>
<?php endforeach; ?>

这是我的解决方案

我将它们转储到一个关联数组中，并将训练总数作为一个键，而不是在处理它们时只回显数据库值。然后可以使用ksort对它们进行排序。完成后，可以使用foreach循环打印出数组

我没有输入完整的数组函数，但它应该会给你一个想法

<?php
$count = 0;

$statement = $db->query('SELECT * FROM workouts');

$workouts = array();

while ($row = mysql_fetch_array($statement)) {

    $total = 0;

    for($i = 0;$i < 13; $i++)
        $total = $total + $row['week'.$i];

    //Build the array containing each teams workouts
    $workouts[$total] = array('team_name' => $row['team_name'],'week1' => $row['week1']);
}

ksort($workouts);

$rowcount = 0;

foreach ($workouts as $total => $team): ?>
    <tr>
    <td><?php echo $rowcount++; ?></td>
    <td><?php echo $team['team_name']; ?></td>
    <td><?php echo $team['week1']; ?></td>
    <td><?php echo $team['week2']; ?></td>
    <td><?php echo $team['week3']; ?></td>
    <td><?php echo $team['week4']; ?></td>
    <td><?php echo $team['week5']; ?></td>
    <td><?php echo $team['week6']; ?></td>
    <td><?php echo $team['week7']; ?></td>
    <td><?php echo $team['week8']; ?></td>
    <td><?php echo $team['week9']; ?></td>
    <td><?php echo $team['week10']; ?></td>
    <td><?php echo $team['week11']; ?></td>
    <td><?php echo $team['week12']; ?></td>
    <td><?php echo $total  ?></td>
    </tr>
<?php endforeach ?>

---

如果我理解正确，您希望团队有序，每个团队中的用户（可能按照他们自己的顺序）

要获得团队订单，您需要加入

with wo as (select wo.*,
                   (week1 + week2 + . . . weekn) as weektotal
            from workouts
           )
select wo.*
from wo join
     (select team_id, sum(weektotal) as weektotal
      from wo
      group by team_id
     ) wot
     on wo.team_id = wot.team_id
order by wot.weektotal desc, wot.team_id, wo.weektotal desc

---

我看不到嵌入的图像。你能描述一下你想要的输出吗？当然，我希望它有一个位置，然后是第1周、第2周、第3周的团队名称，然后是数据库表中所有团队的总数。我还在我的主机上添加了一个新的映像，以帮助您的数据显示在用户级别，但您希望团队井然有序。用户和团队之间的关系是什么？除非用户名是整个团队的单数登录名。我以前见过竞赛跟踪系统将团队本身视为用户，而不是成员。这可能会起作用。我现在试图看到的问题是我的服务器不喜欢mysql\u fetch\u数组（$statement）对不起，可能是foreach（$statement as$row）相反，这是可行的，我只需要在订单末尾添加DESC，以使其正确排序。谢谢你的帮助。很好的解决方案。