Php Mysql选择按日期字段的一部分分组

我有一个应用程序日志表。我目前使用以下查询计算每分钟的操作数

SELECT COUNT(id) 
FROM application_log 
WHERE activity_date LIKE '%2016-11-01 18:12%' AND activity_type = 'Full Invoice' AND status = 'Success'

目前，我必须更改每分钟并重新运行查询

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我有没有办法得到一小时内每分钟的计数？或者通过获取一天中每小时的操作数来进一步了解情况？

使用

DATE\u格式

将时间缩短为分钟，并按分钟分组

SELECT DATE_FORMAT(activity_date, '%H:%i') AS time, COUNT(*)
FROM application_log
WHERE activity_date BETWEEN @start_time AND @end_time
AND activity_type = 'Full Invoice' AND status = 'Success'
GROUP BY time
ORDER BY time

如果时间范围超过一天，请将日期添加到格式字符串中。

希望这有帮助

SELECT  concat(date(activity_date),' ',hour(activity_date),':', minute(activity_date)) as activity_date , COUNT(id) 
FROM application_log 
WHERE activity_type = 'Full Invoice' AND status = 'Success' 
group by date(activity_date),hour(activity_date), minute(activity_date);

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也许这可以给你一些指导：下面的答案对我来说非常有效。谢谢