Php 删除"&引用；（点）在每一个用句型括起来的单词后面

我想删除模式中每个单词后面的“.”（点）

输入：

Lorem *|Ipsum.|* is simply *|dummy.|* text of the *|printing|* and typesetting *|industry.|*.

Lorem *|Ipsum|* is simply *|dummy|* text of the *|printing|* and typesetting *|industry|*.

"Lorem *|Ipsum|* is simply *|dummy|* text of the *|printing|* and typesetting *|industry|*."

输出：

Lorem *|Ipsum.|* is simply *|dummy.|* text of the *|printing|* and typesetting *|industry.|*.

Lorem *|Ipsum|* is simply *|dummy|* text of the *|printing|* and typesetting *|industry|*.

"Lorem *|Ipsum|* is simply *|dummy|* text of the *|printing|* and typesetting *|industry|*."

---

您可以使用此正则表达式捕获带有适当分组的

*|sometext.

模式的文本

(\*\|[^|]+)\.(\|\*)

并替换为

$1$2

，其中

*.\sometext

部分被捕获到组1中，而

被排除在分组之外，因此它被删除，而

*

部分被分组到组2中

$s = "Lorem *|Ipsum.|* is simply *|dummy.|* text of the *|printing|* and typesetting *|industry.|*.";
echo preg_replace('/(\*\|[^|]+)\.(\|\*)/', '$1$2', $s);

$s = "Lorem *|Ipsum.|* is simply *|dummy.|* text of the *|printing|* and typesetting *|industry.|*.";
echo preg_replace('/(\*\|[^|]+)\.(\|\*)/', '$1$2', $s);

打印以下内容，并在

*|文本中删除点。|*

Lorem *|Ipsum|* is simply *|dummy|* text of the *|printing|* and typesetting *|industry|*.

---

我们可以使用str\u replace（）来实现这一点

$string = 'Lorem *|Ipsum.|* is simply *|dummy.|* text of the *|printing|* and typesetting *|industry.|*.';
$replacedString = str_replace('.|', '|', $string);`

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您可以在此处查看有关该功能的更多信息

这可能有助于您做到这一点：

$string = 'Lorem *|Ipsum.|* is simply *|dummy.|* text of the *|printing|* and typesetting *|industry.|*.';

$output = preg_replace('/(\.\|)/s', '|', $string);

var_dump($output);

输出：