Php 如何在转到其他页面时保留url数据

我有从上一页的表单提交的url变量。所以我的url看起来像site.com/submitted.php？first_name=hello&last_name=bye

现在，当我转到第二页时，我使用一个链接来保存提交的变量

在第二个页面上，它基本上是一个下拉列表，使用select标记和一个submit按钮，从mysql服务器生成一个表，然后链接回同一个页面。它看起来像：

<FORM ACTION="secondPage.php?first_name=hello&last_name=bye" METHOD="GET">
    <select name='selectedOption' >
        <option value="op1">option1</option>  
        <option value="op2">option2</option>  
        <option value="op3">option3</option>  
    </select>
    <INPUT TYPE="SUBMIT" VALUE = "Search">
</FORM>

而不是：

secondPage.php?first_name=hello&last_name=bye&selectedOption=op1

---

感谢您的帮助

在第二页。在表单中，在第二页上创建两个隐藏字段。在表单make two hidden fields中，我不确定您希望如何传递数据，但这里有一个建议，可以使用php获得您想要的值

更改此项：

---

我不确定您希望如何传递数据，但这里有一个建议，可以使用php获得所需的值

更改此项：

---

基本上，我一直在做类似的事情，但我发现了一个很好的解决方案和一个很好的方法。。如果您不介意的话，让我给您一些代码作为示例

要有条理并清楚自己所做的事情：-

##**FIRST PAGE** : -
the url: - secondPage.php?first_name=hello&last_name=bye <--- this was the result..

Then you travelled to the 2nd page: - <-- result was still associated

##**SECOND PAGE** : -

$firstname = $_GET['first_name'];
$lastname= $_GET['last_name'];
<FORM ACTION="secondPage.php?first_name=<?php echo $firstname; ?>&last_name=<?php echo $lastname ?>" METHOD="POST">
    <select name='selectedOption' >
        <option value="op1">option1</option>  
        <option value="op2">option2</option>  
        <option value="op3">option3</option>  
    </select>
    <INPUT TYPE="SUBMIT" name ="submit" VALUE = "Search">
</FORM>

##**THIRD PAGE** The page that the form is going to go to: -


$option = $_GET ['selectedOption'];
// you can also get the other data on this page through same method i've done on page two..

---

基本上，我一直在做类似的事情，但我发现了一个很好的解决方案和一个很好的方法。。如果您不介意的话，让我给您一些代码作为示例

要有条理并清楚自己所做的事情：-

##**FIRST PAGE** : -
the url: - secondPage.php?first_name=hello&last_name=bye <--- this was the result..

Then you travelled to the 2nd page: - <-- result was still associated

##**SECOND PAGE** : -

$firstname = $_GET['first_name'];
$lastname= $_GET['last_name'];
<FORM ACTION="secondPage.php?first_name=<?php echo $firstname; ?>&last_name=<?php echo $lastname ?>" METHOD="POST">
    <select name='selectedOption' >
        <option value="op1">option1</option>  
        <option value="op2">option2</option>  
        <option value="op3">option3</option>  
    </select>
    <INPUT TYPE="SUBMIT" name ="submit" VALUE = "Search">
</FORM>

##**THIRD PAGE** The page that the form is going to go to: -


$option = $_GET ['selectedOption'];
// you can also get the other data on this page through same method i've done on page two..

---

使用隐藏字段来记住它们。。如果您使用Tim的方法，请将$\u GET值进行HTML编码。否则，您可能会导致页面损坏，或者更糟糕的是，页面受损。请使用隐藏字段来记住这些页面。。如果您使用Tim的方法，请将$\u GET值进行HTML编码。否则，你最终可能会被破坏，或者更糟糕的是，被破坏的页面。嗯。。。XSS ftw./>警惕‘foo’；嗯。。。XSS ftw./>警惕‘foo’；

// the 'if' statements aren't necessary. just an idea for simple server-side
// validation

if(isset($_REQUEST['selectedOption']) && $_REQUEST['selectedOption'] != ''){
    $option = $_REQUEST['selectedOption'];
}

if(isset($_REQUEST['first_name']) && $_REQUEST['first_name'] != ''){
    $fname = $_REQUEST['first_name'];
}

if(isset($_REQUEST['last_name']) && $_REQUEST['last_name'] != ''){
    $lname = $_REQUEST['last_name'];
}

##**FIRST PAGE** : -
the url: - secondPage.php?first_name=hello&last_name=bye <--- this was the result..

Then you travelled to the 2nd page: - <-- result was still associated

##**SECOND PAGE** : -

$firstname = $_GET['first_name'];
$lastname= $_GET['last_name'];
<FORM ACTION="secondPage.php?first_name=<?php echo $firstname; ?>&last_name=<?php echo $lastname ?>" METHOD="POST">
    <select name='selectedOption' >
        <option value="op1">option1</option>  
        <option value="op2">option2</option>  
        <option value="op3">option3</option>  
    </select>
    <INPUT TYPE="SUBMIT" name ="submit" VALUE = "Search">
</FORM>

##**THIRD PAGE** The page that the form is going to go to: -


$option = $_GET ['selectedOption'];
// you can also get the other data on this page through same method i've done on page two..