Php 如何解析嵌套的json并将其存储到mysql数据库中？

我对PHP一无所知，有人能帮我如何将嵌套的JSON数据存储到数据库中吗？我编写代码，但每次只针对一行，但如果我想解析嵌套的JSON，我该怎么做

[
        {
        "product_name": "Product3",
        "product_price": "500",
        "product_quantity": "5",
        "userid": "1",
        "orderid": "1"
    },
        {
        "product_name": "Product4",
        "product_price": "500",
        "product_quantity": "5",
        "userid": "1",
        "orderid": "1"
    },
        {
        "product_name": "Product5",
        "product_price": "500",
        "product_quantity": "5",
        "userid": "1",
        "orderid": "1"
    }

]

---

我试图插入使用邮递员，但只有一个空白行插入。请帮助我如何在命中API后将其存储到数据库中？

使用循环插入json值。我还没有测试过，但我认为它对你有用

// Creating MySQL connection.
$con = mysqli_connect($HostName,$HostUser,$HostPass,$DatabaseName);

// Storing the received JSON in $json.
$json = file_get_contents('php://input');

// Decode the received JSON and store into $obj
$obj = json_decode($json,true);

foreach($obj as $product) : 

  $productid = $product['product_id'];
  $productname = $product['product_name'];
  $productprice = $product['product_price'];
  $productquantity = $product['product_quantity'];
  $userid = $product['userid'];
  $orderid = $product['orderid'];

  if(!empty($productid)) :
    $query = "INSERT INTO order_product (product_id, product_name, product_price, 
   product_quantity, userid, orderid) VALUES 
('$productid','$productname','$productprice','$productquantity','$userid','$orderid')";

    if(mysqli_query($con,$query)){

       // On query success it will print below message.
      $MSG = 'Data Successfully Submitted.' ;

      // Converting the message into JSON format.
      $json = json_encode($MSG);

      // Echo the message.
     echo $json ;

    }
    else{

     echo 'Try Again';

    }
  endif;
endforeach;

---

添加一个循环，并对该循环中的单个对象执行当前正在执行的操作…

// Creating MySQL connection.
$con = mysqli_connect($HostName,$HostUser,$HostPass,$DatabaseName);

// Storing the received JSON in $json.
$json = file_get_contents('php://input');

// Decode the received JSON and store into $obj
$obj = json_decode($json,true);

foreach($obj as $product) : 

  $productid = $product['product_id'];
  $productname = $product['product_name'];
  $productprice = $product['product_price'];
  $productquantity = $product['product_quantity'];
  $userid = $product['userid'];
  $orderid = $product['orderid'];

  if(!empty($productid)) :
    $query = "INSERT INTO order_product (product_id, product_name, product_price, 
   product_quantity, userid, orderid) VALUES 
('$productid','$productname','$productprice','$productquantity','$userid','$orderid')";

    if(mysqli_query($con,$query)){

       // On query success it will print below message.
      $MSG = 'Data Successfully Submitted.' ;

      // Converting the message into JSON format.
      $json = json_encode($MSG);

      // Echo the message.
     echo $json ;

    }
    else{

     echo 'Try Again';

    }
  endif;
endforeach;