can'；t使用angular和php使用下拉列表获取数据

我正在用angular和php构建一个项目。我的数据库中有一个“客户”表。我正在尝试从下拉列表中的“Customers”表中获取所有名称，但它不起作用。控制台目前没有显示任何错误。有人能查一下我的密码吗

Html:

Php

---

您应该获得

响应。数据

，而不仅仅是

响应

，如下所示：

$scope.customersDetails = response.data;

---

另外，我建议您使用而不是

ngRepeat

指令。

您应该获得

响应。数据

而不仅仅是

响应

，如下所示：

$scope.customersDetails = response.data;

---

另外，我建议您使用而不是

ngRepeat

指令。

您的PHP文件有一些问题

1-没有客户类别。（我想这个例子你不需要）

2-$queryResult2=array（）；您创建了一个数组，但没有提供数据

3-您对空数组进行了编码

4-您尝试对已编码的数据进行编码

请检查固定示例：

<?php
  header('Content-Type: text/html; charset=utf-8');
  $connection = mysqli_connect('localhost','root','','hamatkin');

  mysqli_query($connection,"SET character_set_client = utf8");
  mysqli_query($connection,"SET character_set_connection = utf8");
  mysqli_query($connection,"SET character_set_results = utf8");

  if(!$connection){
    die("couldnt connect".mysqli_error);
  }

    /*
    I dont know if you have 'Customer' class    
    */
  // $customer = new Customer(); 

// $query = "SELECT * FROM `customers`";
    $query = "SELECT customer_id, full_name FROM `customers`";
  $queryResult = $connection->query($query);
  $queryResult2 = array();
  if( $queryResult->num_rows>0){
    $i = 0;
    while($row = $queryResult->fetch_assoc()){
        // if you dont have Customer class, there is no $customer->....
    // $customer->customer_id = $row['customer_id']
        // $customer->full_name =$row['full_name']

    // put the data in $queryResult2
    // $queryResult2[$i]['customer_id'] = $row['customer_id'];
    // $queryResult2[$i]['full_name'] = $row['full_name'];
// OR   
$queryResult2[] = $row;

    $i++;
    }
  }

  header('Content-type:application/json');
  $queryResult3 = json_encode($queryResult2);
  // echo json_encode($queryResult3); // you don't need to encode again.
  echo $queryResult3;
?>

---

您的PHP文件有一些问题

1-没有客户类别。（我想这个例子你不需要）

2-$queryResult2=array（）；您创建了一个数组，但没有提供数据

3-您对空数组进行了编码

4-您尝试对已编码的数据进行编码

请检查固定示例：

<?php
  header('Content-Type: text/html; charset=utf-8');
  $connection = mysqli_connect('localhost','root','','hamatkin');

  mysqli_query($connection,"SET character_set_client = utf8");
  mysqli_query($connection,"SET character_set_connection = utf8");
  mysqli_query($connection,"SET character_set_results = utf8");

  if(!$connection){
    die("couldnt connect".mysqli_error);
  }

    /*
    I dont know if you have 'Customer' class    
    */
  // $customer = new Customer(); 

// $query = "SELECT * FROM `customers`";
    $query = "SELECT customer_id, full_name FROM `customers`";
  $queryResult = $connection->query($query);
  $queryResult2 = array();
  if( $queryResult->num_rows>0){
    $i = 0;
    while($row = $queryResult->fetch_assoc()){
        // if you dont have Customer class, there is no $customer->....
    // $customer->customer_id = $row['customer_id']
        // $customer->full_name =$row['full_name']

    // put the data in $queryResult2
    // $queryResult2[$i]['customer_id'] = $row['customer_id'];
    // $queryResult2[$i]['full_name'] = $row['full_name'];
// OR   
$queryResult2[] = $row;

    $i++;
    }
  }

  header('Content-type:application/json');
  $queryResult3 = json_encode($queryResult2);
  // echo json_encode($queryResult3); // you don't need to encode again.
  echo $queryResult3;
?>

问题出在php代码$queryResult2=array（）中；那么？@B.Kocaman很抱歉，我是新手，我该怎么办？问题在于您的php代码$queryResult2=array（）；那么？@B.Kocaman对不起，我是新手，我该怎么办？
<?php
  header('Content-Type: text/html; charset=utf-8');
  $connection = mysqli_connect('localhost','root','','hamatkin');

  mysqli_query($connection,"SET character_set_client = utf8");
  mysqli_query($connection,"SET character_set_connection = utf8");
  mysqli_query($connection,"SET character_set_results = utf8");

  if(!$connection){
    die("couldnt connect".mysqli_error);
  }

    /*
    I dont know if you have 'Customer' class    
    */
  // $customer = new Customer(); 

// $query = "SELECT * FROM `customers`";
    $query = "SELECT customer_id, full_name FROM `customers`";
  $queryResult = $connection->query($query);
  $queryResult2 = array();
  if( $queryResult->num_rows>0){
    $i = 0;
    while($row = $queryResult->fetch_assoc()){
        // if you dont have Customer class, there is no $customer->....
    // $customer->customer_id = $row['customer_id']
        // $customer->full_name =$row['full_name']

    // put the data in $queryResult2
    // $queryResult2[$i]['customer_id'] = $row['customer_id'];
    // $queryResult2[$i]['full_name'] = $row['full_name'];
// OR   
$queryResult2[] = $row;

    $i++;
    }
  }

  header('Content-type:application/json');
  $queryResult3 = json_encode($queryResult2);
  // echo json_encode($queryResult3); // you don't need to encode again.
  echo $queryResult3;
?>