在另一个数组php foreach中获取数组值

我有一个数组

Array
(
    [0] => Array
        (
            [folding_knives__no_assist__possession19] => G
            [folding_knives__no_assist__possession___length20] => 
            [folding_knives__no_assist___open_cary21] => G
            [folding_knives__no_assist__open_carry_length22] => 
            [folding_knives__no_assist__concealed23] => G
            [folding_knives__no_assisted__concealed_length24] => 
            [folding_knives__no_assist__concealed_w__ccw_required25] => R
            [folding_knives__no_assist__concealed_w__ccw_required_l26] => 
            [folding_knives__no_assist___notes27] => 
        )

    [1] => Array
        (
            [folding_knives__assisted_opening__possession28] => G
            [folding_knives__assisted_opening__possession_length29] => 
            [folding_knives__assisted_opening__open_carry30] => G
            [folding_knives__assisted_opening__open_carry_length31] => 
            [folding_knives__assisted_opening___concealed32] => G
            [folding_knives__assisted_opening__concealed_length33] => 
            [folding_knives__assisted_opening___concealed_w__ccw_re34] => R
            [folding_knives__assisted_opening__concealed_w__ccw_req35] => 
            [folding_knives___assisted_opening___notes36] => 
        )
)

我已尝试将数组数据显示到另一个数组中，但无法

foreach ($chunks as $key => $val)
{

                $allknife[] = array( 
                        'name'=>$key[0],
                        'possession'=>$val[0],
                        'possession_length'=>$val[1]                    
                    );


}

此处名称“=>$key[0]此处将是arry首项密钥，如折刀\uuuuu no\uu辅助\uuuu占有19

由于您的数组具有不一致的密钥名称，您不能依赖此项，首先需要一致的名称

按如下方式映射阵列：

array(
    0 => array(
        'assist' => true,
        'open_carry_nr' => 21,
        'open_carry_length' => 22
        // and so on...
    ),

    2 => array(
        'assist' => false,
        'open_carry_nr' => 18,
        'open_carry_length' => 1337
        // and so on...
    )
);

---

更好的做法。

应该是链接这个，你需要字段计数链接1/2/3/4。。。然后必须使用标志逻辑，如i=0；而我++

$allknife[] = array();
foreach ($chunks as $key => $val)
{
   $allknife['name']=>$val['yourvaluesoeshere'],
   $allknife['possession']=>$val['yourvaluesoeshere'],
   $allknife['possession_length']=>$val['yourvaluesoeshere']                    
}

---

不，本例中的键将是0、1、2…现在我如何解决这个@matiitmake other foreach^^您的键将是折叠刀具、不使用辅助工具、占有19，但不要使用索引，否则您的键将是F这是错误的$Key['folding_刀具、不使用辅助工具、占有19']不存在。在这种情况下，必须避免不一致的键名。