Php使用api键获取数据
我想做一个PHP页面发送喜欢的API从社会媒体面板,我有一个成员 他们给了我这个例子,但我不完全理解 示例代码:Php使用api键获取数据,php,api,Php,Api,我想做一个PHP页面发送喜欢的API从社会媒体面板,我有一个成员 他们给了我这个例子,但我不完全理解 示例代码: <?php class Api { public $api_url = 'http://domain/api/v2'; // API URL public $api_key = ''; // Your API key public function order($data) { // add order $po
<?php
class Api
{
public $api_url = 'http://domain/api/v2'; // API URL
public $api_key = ''; // Your API key
public function order($data) { // add order
$post = array_merge(array('key' => $this->api_key, 'action' => 'add'), $data);
return json_decode($this->connect($post));
}
public function status($order_id) { // get order status
return json_decode($this->connect(array(
'key' => $this->api_key,
'action' => 'status',
'id' => $order_id
)));
}
public function services() { // get services
return json_decode($this->connect(array(
'key' => $this->api_key,
'action' => 'services',
)));
}
public function balance() { // get balance
return json_decode($this->connect(array(
'key' => $this->api_key,
'action' => 'balance',
)));
}
private function connect($post) {
$_post = Array();
if (is_array($post)) {
foreach ($post as $name => $value) {
$_post[] = $name.'='.urlencode($value);
}
}
$ch = curl_init($this->api_url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
if (is_array($post)) {
curl_setopt($ch, CURLOPT_POSTFIELDS, join('&', $_post));
}
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)');
$result = curl_exec($ch);
if (curl_errno($ch) != 0 && empty($result)) {
$result = false;
}
curl_close($ch);
return $result;
}
}
// Examples
$api = new Api();
$services = $api->services(); # return all services
$balance = $api->balance(); # return user balance
// add order
$order = $api->order(array('service' => 1, 'link' => 'http://example.com/test', 'quantity' => 100)); # Default
$order = $api->order(array('service' => 1, 'link' => 'http://example.com/test', 'quantity' => 100, 'keywords'=>"test, testing")); # SEO
$order = $api->order(array('service' => 1, 'link' => 'http://example.com/test', 'comments' => "good pic\ngreat photo\n:)\n;)")); # Custom Comments
$order = $api->order(array('service' => 4, 'link' => 'http://example.com/test', 'quantity' => 100, 'usernames'=>"test, testing", 'hashtags'=>"#goodphoto")); # Mentions with Hashtags
$order = $api->order(array('service' => 5, 'link' => 'http://example.com/test', 'usernames' => "test\nexample\nfb")); # Mentions Custom List
$order = $api->order(array('service' => 6, 'link' => 'http://example.com/test', 'quantity' => 100, 'hashtag'=>"test")); # Mentions Hashtag
$order = $api->order(array('service' => 7, 'link' => 'http://example.com/test', 'quantity' => 1000, 'username'=>"test")); # Mentions User Followers
$order = $api->order(array('service' => 8, 'link' => 'http://example.com/test', 'quantity' => 1000, 'media'=>"http://example.com/p/Ds2kfEr24Dr")); # Mentions Media Likers
$order = $api->order(array('service' => 9, 'link' => 'http://example.com/test', 'quantity' => 1000, 'usernames'=>"test")); # Mentions
$order = $api->order(array('service' => 10, 'link' => 'http://example.com/test')); # Package
$order = $api->order(array('service' => 12, 'link' => 'http://example.com/test', 'quantity' => 100, 'runs' => 10, 'interval' => 60)); # Drip-feed
$order = $api->order(array('service' => 11, 'username' => 'username', 'min' => 100, 'max' => 110, 'posts' => 0,'delay' => 30)); # Subscriptions
$status = $api->status($order->order); # return status, charge, remains, start count
?>
现在,我想在我的PHP页面上看到“获取平衡”,但我做不到。我填写API URL和API密钥。你能帮我做什么吗
谢谢您可以通过在API上调用
balance()
来使用它,就像这样
$api=newapi();
$response=$api->balance();
//响应具有“余额”和“货币”属性,可以这样访问;
呼应“你的平衡是”$回应->平衡。" " . $响应->货币;
投票否决,因为它过于宽泛,主要是基于意见-您可以对此进行研究,oAuth 2.0也是一个问答,如果您在现有代码中遇到某些特定问题,我们可以帮助您,但我们不是来为您编写的。您链接到的cde(应该包含在实际问题中)只是一个类。由于这基本上是PHP 101,我建议您阅读一些关于PHP和OOP的入门教程,因为您肯定会很快遇到更多的问题。感谢您的回答,但我收到了以下错误“可捕获的致命错误:stdClass类的对象无法在第71行转换为字符串”@Can1-该错误发生在哪个文件中?在您显示的代码的第71行中,我看不到任何“对象到字符串”的转换。我在页面末尾添加了@jack wilsdon代码,这些代码给出了该错误。现在我试着用“print_r($balance)”,而不是“echo$balance”,我得到了这些“stdClass对象([balance]=>0.45912[currency]=>USD)”我怎么能只得到余额部分?@Can1-当然。这些方法返回对象。Do:$data=$api->balance()代码>要回送它,您还应该检查是否得到了有效的响应:echo-isset($data->balance)$数据->余额:“无效响应”代码>。添加了解释如何访问返回对象属性的代码。