Php Laravel 5在选择查询中选择

我有一个php网站。我想把它改写成拉威尔5。问题在于：

    $getAllTrainings = $db->getAll('SELECT * from add_timetable WHERE active_before >= CURDATE() AND complete = ?i', 0);

        foreach ($getAllTrainings as $training) {
            $currentTraining = $db->getOne('SELECT service_id from add_people WHERE service_card = ?s AND training_id = ?s', $service_card, $training['code']);
            if($currentTraining) {
                   $reg_button = <<<ECHO BUTTON_1
            }  else {
                   $reg_button = <<<ECHO BUTTON_2
            }
            echo <<<TRAINING
        <div class="training__item" id="{$training['code']}" >
        <h3>{$training['header']}</h3>
        <p>{$training['description']}</p>
        <div class="datetime is-flex">
            <div class="date">
                {$training['date']}
            </div>
            <div class="time">
                {$training['time']}
                <div class="small">
                    {$training['place']}
                </div>
            </div>
        </div>
        {$reg_button}
    </div>
TRAINING;
        }

$getAllTrainings=$db->getAll（'SELECT*from add_timeline，其中活动时间在>=CURDATE（）之前，完成时间为？'i'，0）；
foreach（$getAllTrainings作为$training）{
$currentTraining=$db->getOne（'从添加人员中选择服务id，其中服务卡=？s和培训id=？s'，$service卡，$training['code']）；
如果（$currentTraining）{
$reg_button=首先需要创建名为“Training”的模型（运行命令：php artisan make:model Training），然后在控制器中加载模型（使用App\Training；），然后运行集合：

$trainings = Training::where('complete', 1)->whereDate('active_date', '>=', Carbon::now()')
// note the Carbon usage, you will need to add it by adding use Carbon;

foreach($trainings as $training){
   // do something with your collection here.
}

当然，您需要在数据库中拥有该表，并建立连接，如果没有，则需要了解有关迁移的更多信息，制作一个表“Trainings”并进行迁移。
什么是

$trainings = Training::where('complete', 1)->whereDate('active_date', '>=', Carbon::now()')
// note the Carbon usage, you will need to add it by adding use Carbon;

foreach($trainings as $training){
   // do something with your collection here.
}