使用PHP从JSON获取请求
您好,我想在PHP中显示此JSON的结果,我有以下内容:使用PHP从JSON获取请求,php,json,Php,Json,您好,我想在PHP中显示此JSON的结果,我有以下内容: $r = {"person1":{"id":100,"name":"Robert"}} $obj = json_decode($r); Name: <?php echo $obj->{'name'};?><br> $r={“person1”:{“id”:100,“name”:“Robert”} $obj=json_解码($r
$r = {"person1":{"id":100,"name":"Robert"}}
$obj = json_decode($r);
Name: <?php echo $obj->{'name'};?><br>
$r={“person1”:{“id”:100,“name”:“Robert”}
$obj=json_解码($r);
名称:
如何正确显示它?您忘记在对象上添加
person1
<?php
$r = '{"person1":{"id":100,"name":"Robert"}}';
$obj = json_decode($r);
echo $obj->person1->name; //"prints" Robert
echo $obj->person1->id; //"prints" 100
这样使用,输出将采用关联数组格式
$array = json_decode($r,true);
print_r($array);
$r = {"person1":{"id":100,"name":"Robert"}}
$obj = json_decode($r);
var_dump($obj); // this will show you $obj structure