Php 3使用1查询和限制进行MYSQL查询

以下是我的php代码：

 $trsql = "SELECT * from members order by id desc";
  $trresult = mysql_query($trsql);
  $count = mysql_num_rows($trresult);
  while ($trrow = mysql_fetch_array($trresult)) {
  $bill_membertotal = mysql_query("SELECT * FROM billing WHERE suite='$trrow[suite]' order by bill_id desc limit 1"); 
  $bill_membercount = mysql_fetch_array($bill_membertotal);
  $check_membertotal = mysql_query("SELECT SUM(net) AS checker FROM billing WHERE suite='$trrow[suite]'"); 
  $check_membercount = mysql_fetch_assoc($check_membertotal);

echo $trrow['col1'] $trrow['col2'] $trrow['col1'] $bill_membercount['balance']  $check_membercount['checker'] ;
}

成员表： [id套件第1列第2列第3列] 计费表： [账单id套房总费用净余额]

问题：如何使用1查询进行此3查询？我知道MYSQL的连接函数。但是在这种情况下怎么办？

未测试：

select * , 
        (select count(*) from members) as members_count,
        (select count(*) from billing where suite = bill.suite) as bill_count,
        (select count(*) from billing where suite = check.suite) as check_count,
from members members
inner join billing  bill on members.suite = bill.suite
inner join billing check members.suite = check.suite

$query = "SELECT
    `member`.`col1` AS `col1`,
    `member`.`col2` AS `col2`,
    `bill`.`balance` AS `balance`,
    SUM(`bill`.`net`) AS `checker`
FROM
    `members` AS `member`,
    `billing` AS `bill`,
WHERE
    `bill`.`suite`=`member`.`suite`
ORDER BY
    `member`.`id`,
    `bill`.`bill_id`
DESC";
$results    = mysql_query($query);
$count      = mysql_num_rows($results);

while($entry = mysql_fetch_array($results)) {
    printf('%s, %s, %s, %s, %s', $entry['col1'], $entry['col2'], $entry['col1'], $entry['balance'], $entry['checker']);
}

mysql.*被标记为已弃用

未测试：

$query = "SELECT
    `member`.`col1` AS `col1`,
    `member`.`col2` AS `col2`,
    `bill`.`balance` AS `balance`,
    SUM(`bill`.`net`) AS `checker`
FROM
    `members` AS `member`,
    `billing` AS `bill`,
WHERE
    `bill`.`suite`=`member`.`suite`
ORDER BY
    `member`.`id`,
    `bill`.`bill_id`
DESC";
$results    = mysql_query($query);
$count      = mysql_num_rows($results);

while($entry = mysql_fetch_array($results)) {
    printf('%s, %s, %s, %s, %s', $entry['col1'], $entry['col2'], $entry['col1'], $entry['balance'], $entry['checker']);
}

---

mysql.*被标记为已弃用

不确定，但请尝试一下，因为这是您的报告所期望的

查询：

SELECT m.*, COUNT(b.id) as member_count, SUM(net) as checker
FROM member m
JOIN billing b ON m.suite = b.suite
GROUP BY b.suite

---

不确定，但请尝试一下，因为这是您的报告所期望的

查询：

SELECT m.*, COUNT(b.id) as member_count, SUM(net) as checker
FROM member m
JOIN billing b ON m.suite = b.suite
GROUP BY b.suite

---

这似乎会产生预期的结果；因为您只需要一个字段的最后一张账单，而MySQL没有分析函数，所以子查询将比连接更容易解决该字段

SELECT id member_id, col1, col2, col3,
  (SELECT balance 
   FROM billing b1 
   WHERE b1.suite=m.suite 
   ORDER BY bill_id DESC LIMIT 1) balance,
   SUM(net) AS checker
FROM members m
LEFT JOIN billing b
  ON m.suite = b.suite
GROUP BY col1,col2,col3,id
ORDER BY id DESC

---

.

这似乎给出了预期的结果；因为您只需要一个字段的最后一张账单，而MySQL没有分析函数，所以子查询将比连接更容易解决该字段

SELECT id member_id, col1, col2, col3,
  (SELECT balance 
   FROM billing b1 
   WHERE b1.suite=m.suite 
   ORDER BY bill_id DESC LIMIT 1) balance,
   SUM(net) AS checker
FROM members m
LEFT JOIN billing b
  ON m.suite = b.suite
GROUP BY col1,col2,col3,id
ORDER BY id DESC

---

.

您能否发布所需的db架构和预期报告列，然后使用JoinsSakhale posted Thank轻松演示您发布所需的db架构和预期报告列，然后很容易演示如何使用JoinsSakhale posted Thanksy您可以使用group by。根据您需要的数据，我刚才编写的查询将返回您不需要的3个查询的所有信息。您将收到一列，其中包含所需的总值。这意味着每一行将包含您需要的所有3个总计的值。@zionbenyacov如果您查看原始查询，则不是它们所要的计数。您可以使用group by after根据您需要的数据，我刚才编写的查询将返回您不需要的3个查询的所有信息。您将收到一列，其中包含所需的总值。这意味着每一行将包含您需要的所有3个总计的值。@zionbenyacov如果您查看原始查询，则不是它们所追求的计数。如果您需要限制，请添加这些？没有主动性！如果你需要一个限制，加上这些？没有主动性！呃。你能用实际的表模式和一些示例值更新上面的sql FIDLE吗：）@MoyedAnsari-查询中编写的

成员

表是关于在SQLFIDDLE中创建的表的：）@MoyedAnsari-成员表在查询中编写的是关于在sqlfiddleI中创建的表的，这在php中是新的。您的脚本在sqlfifle上运行得很好，但我不能在我的php脚本中打印结果。我是php新手。您的脚本在sqlfifle上运行得很好，但我无法在我的php脚本中打印结果。