如何获得<；李>；使用PHPDOM方法的内部html

如何使用php

DOM

方法获取

内部html这些是php字符串变量ihave中用于过滤li内部html的内容

<div class="cModule myphotos">
<h3><span>My photos</span></h3>
 <ul class="cResetList cThumbList clrfix">
     <li>
          <a href="/projects/mysportsjam/index.php/joom-social/103-shine/photos/photo?albumid=12#photoid=67" hidefocus="true" style="outline: none;"><img class="cAvatar jomNameTips cAvatar-sidebar" title="Uploaded by shine s" src="http://107.20.167.165/projects/mysportsjam/images/photos/103/12/thumb_05c0beeb8f0f32a08538dad7.jpg" alt="shine s"></a>
    </li>

    <li>
    <a href="/projects/mysportsjam/index.php/joom-social/103-shine/photos/photo?albumid=12#photoid=43" hidefocus="true" style="outline: none;"><img class="cAvatar jomNameTips cAvatar-sidebar" src="http://107.20.167.165/projects/mysportsjam/images/photos/103/12/thumb_c122ff8dafd2edeba377a1cd.jpg" alt="shine s" original-title="Uploaded by shine s"></a>
    </li>

    <li>
    <a href="/projects/mysportsjam/index.php/joom-social/103-shine/photos/photo?albumid=12#photoid=66" hidefocus="true" style="outline: none;"><img class="cAvatar jomNameTips cAvatar-sidebar" title="Uploaded by shine s" src="http://107.20.167.165/projects/mysportsjam/images/photos/103/12/thumb_9414b5dff6c8644d197ff684.jpg" alt="shine s"></a>
    </li>
            </ul>

    <div class="app-box-footer">
    <a href="/projects/mysportsjam/index.php/joom-social/103-shine/photos" hidefocus="true" style="outline: none;">View all photos</a>
</div>
    </div>

我的照片

如何过滤内部html href链接和图像标记

你可以用它

示例代码显示了如何获取

href

属性。我想你可以自己弄清楚如何获得图像的

src

<?php

$xml = new DOMDocument();
$xml->loadHTML($body);

$nodes = $xml->getElementsByTagName('li');

for($curr = 0; $curr < $nodes->length; $curr++) {
    $li = $nodes->item($curr);

    $innerHTML= '';
    $children = $li->childNodes;
    foreach ($children as $child) {
        $innerHTML .= $child->ownerDocument->saveXML( $child );
    }

    print $innerHTML;

    foreach($li->childNodes as $child) {
        $a = $child;

        if(is_a($a, "DOMElement")) {
            $href = $a->getAttribute('href');

            print "{$href}\n";
        }
    }

    print "\n";
}

loadHTML（$body）；
$nodes=$xml->getElementsByTagName（'li'）；
对于（$curr=0；$curr<$nodes->length；$curr++）{
$li=$nodes->item（$curr）；
$innerHTML=''；
$children=$li->childNodes；
foreach（$childrenas$child）{
$innerHTML.=$child->ownerDocument->saveXML（$child）；
}
打印$innerHTML；
foreach（$li->childNodes作为$child）{
$a=$child；
如果（是a（$a，“DOMElement”））{
$href=$a->getAttribute（'href'）；
打印“{$href}\n”；
}
}
打印“\n”；
}

您尝试过什么？包括您的PHP代码，否则看起来您只是要求我们为您编写代码。因此，您希望获取

href

和

src

中的值？我想，OP want就是整个innerHTML。在文档中，如果OP已经阅读了这些文档。