PHP:For循环只迭代一次

我有一个用于php游戏的函数，其中有一个用于检查房间ID的循环。基本上，for循环只运行一次，而它应该运行两次。下面的代码块演示了（$i的第一个for循环）：

//成功的sql登录&$player已正确设置为“”，并且所有设置均低于sql
//语句执行正确$计数是2
功能设置怪物位置（$player，$rooms\u id）{
如果（mysql_结果（mysql_查询（“选择当前状态，其中player=$player和items_id为NULL，monsters_id为NULL，quantity为NULL，rooms_id不为NULL”），0）==0）{
$sql=mysql\u query（“从当前位置选择COUNT（*），其中player=$player和items\u id为空，monsters\u id>100，monsters\u id<300”）；
$count=mysql\u结果（$sql，0）；
$sql=mysql\u query（“从当前位置选择怪物\u id，其中player=$player和items\u id为空，怪物\u id>100，怪物\u id<300，按怪物\u id排序”）；
对于（$i=0；$i<$count；$i+=1）{
$sql=mysql\u query（“从当前位置选择怪物\u id，其中player=$player和items\u id为空，怪物\u id>100，怪物\u id<300，按怪物\u id排序”）；
$result=mysql\u result（$sql，$i）；
如果（mysql_结果（mysql_查询（“从当前位置选择计数（*），其中player=$player和items_id为空，monsters_id=$result和quantity=1”），0）==1）{
$final=-1；
$array[1]=$rooms\u id-1；
$array[2]=$rooms\u id+1；
$array[3]=$rooms\u id-100；
$array[4]=$rooms\u id+100；
$array[5]=$rooms\u id-200；
$array[6]=$rooms\u id-101；
$array[7]=$rooms\u id-99；
$array[8]=$rooms\u id-2；
$array[9]=$rooms\u id+200；
$array[10]=$rooms\u id+101；
$array[11]=$rooms\u id+99；
$array[12]=$rooms\u id+2；
如果（$result<200）{
对于（$j=1；$j<5；$j+=1）{
$sql=mysql\u query（“从当前位置选择COUNT（*），其中player=$player，items\u id为NULL，monsters\u id不为NULL，rooms\u id={$array[$j]}”）；
$count=mysql\u结果（$sql，0）；
$sql=mysql\u查询（“从房间中选择计数（*）（房间id={$array[$j]}）”；
$roompresent=mysql\u结果（$sql，0）；
如果（$count==0，$final==1，$roompresent==1）{
$final=$array[$j]；
}
}
}否则，如果（$result>200）{
对于（$k=1；$k<13；$k+=1）{
$sql=mysql\u query（“从当前位置选择COUNT（*），其中（player=$player和items\u id为NULL，monsters\u id不为NULL，rooms\u id={$array[$k]}）”；
$count=mysql\u结果（$sql，0）；
$sql=mysql_查询（“从房间中选择计数（*）（房间id={$array[$k]}）”；
$roompresent=mysql\u结果（$sql，0）；
如果（$count==0和$final==1和$roompresent==1）{$final=$array[$k]；}
}
如果（$final==-1）{
$sql=mysql_查询（“从房间中选择计数（*））；
$count=mysql\u结果（$sql，0）；
$sql=mysql_查询（“从房间中选择房间id”）；
对于（$l=0；$l<$count；$l+=1）{
$rooms=mysql\u查询（$sql，$l）；
$sql=mysql\u query（“从当前位置选择COUNT（*），其中player=$player，items\u id为NULL，monsters\u id不为NULL，rooms\u id=$rooms”）；
如果（mysql_result（$sql，0）==0和$final=-1）{$final=$rooms；}
}
}
}
if（$final！=-1）{$sql=mysql\u query（“更新当前设置房间\u id=$final，其中player=$player和items\u id为空，monsters\u id=$result；”）；}
else{$sql=mysql\u query（“更新当前设置房间\u id=-1，其中player=$player和items\u id为空，monsters\u id=$result”）；}
}
}
$sql=mysql\u query（“更新当前设置状态=1，其中player=$player和items\u id为NULL，monsters\u id为NULL，quantity为NULL，rooms\u id不为NULL”）；
}否则{
$sql=mysql\u query（“更新当前设置状态=0，其中player=$player和items\u id为NULL，monsters\u id为NULL，quantity为NULL，rooms\u id不为NULL”）；
}

}

当$count为2时，for循环只运行一次。我通过在每次for循环运行时向mysql表中的值添加1来验证这一点。该值仅增加一次

---

顶部的if语句是每隔一个勾号运行一次函数。

for循环的条件部分在循环的每次迭代中都进行计算，因此您不能在主循环中更改

$count

的值。您需要将变量名更改为更有意义的名称

试试这个：

// successful sql login & $player is correctly set with '', and all below sql
// statements execute correctly. $count is 2
function setMonstersLocation($player,$rooms_id){
if (mysql_result(mysql_query("SELECT state FROM present WHERE player = $player AND items_id IS NULL AND monsters_id IS NULL AND quantity IS NULL AND rooms_id IS NOT NULL"),0) == 0){
    $sql = mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id > 100 AND monsters_id < 300");
    // Note here I've changed $count to $playerCount, because it is a count of the
    // number of players.
    $playerCount = mysql_result($sql,0);
    $sql = mysql_query("SELECT monsters_id FROM present WHERE player = $player AND items_id IS NULL AND monsters_id > 100 AND monsters_id < 300 ORDER BY monsters_id");
    for ($i = 0; $i < $playerCount; $i+= 1) {
        $sql = mysql_query("SELECT monsters_id FROM present WHERE player = $player AND items_id IS NULL AND monsters_id > 100 AND monsters_id < 300 ORDER BY monsters_id");
        $result = mysql_result($sql,$i);
        if (mysql_result(mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id=$result AND quantity = 1"),0) == 1){
            $final = -1;
            $array[1] = $rooms_id - 1;
            $array[2] = $rooms_id + 1;
            $array[3] = $rooms_id - 100;
            $array[4] = $rooms_id + 100;
            $array[5] = $rooms_id - 200;
            $array[6] = $rooms_id - 101;
            $array[7] = $rooms_id - 99;
            $array[8] = $rooms_id - 2;
            $array[9] = $rooms_id + 200;
            $array[10] = $rooms_id + 101;
            $array[11] = $rooms_id + 99;
            $array[12] = $rooms_id + 2;
            if ($result < 200){
                for ($j = 1; $j < 5; $j+=1){
                    $sql = mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id IS NOT NULL AND rooms_id={$array[$j]}");
                    // Note here I've change $count to $presentCount, because you're
                    // counting the number of presents? (Whatever presents are)
                    $presentCount = mysql_result($sql,0);
                    $sql = mysql_query("SELECT COUNT(*) FROM rooms WHERE (rooms_id={$array[$j]})");
                    $roompresent = mysql_result($sql,0);
                    if ($presentCount == 0 and $final == -1 and $roompresent == 1){
                        $final = $array[$j];
                    }
                }
            } else if ($result > 200){
                for ($k = 1; $k < 13; $k+=1){
                    $sql = mysql_query("SELECT COUNT(*) FROM present WHERE (player = $player AND items_id IS NULL AND monsters_id IS NOT NULL AND rooms_id={$array[$k]})");
                    // You can use $presentCount again here, because it's a 
                    // different code block to the previous one.
                    // This doesn't mean its in a different SCOPE, however.
                    $presentCount = mysql_result($sql,0);
                    $sql = mysql_query("SELECT COUNT(*) FROM rooms WHERE (rooms_id={$array[$k]})");
                    $roompresent = mysql_result($sql,0);
                    if ($presentCount == 0 and $final == -1 and $roompresent == 1){ $final = $array[$k]; }
                }
                if ($final == -1){
                    $sql = mysql_query("SELECT COUNT(*) FROM rooms");
                    // Note here I've change $count to $roomsCount, because you're 
                    // counting the number of rooms.
                    $roomsCount = mysql_result($sql,0);
                    $sql = mysql_query("SELECT rooms_id FROM rooms");
                    for ($l = 0; $l < $roomsCount; $l+=1){
                        $rooms = mysql_query($sql,$l);
                        $sql = mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id IS NOT NULL AND rooms_id=$rooms");
                        if (mysql_result($sql,0) == 0 and $final == -1){ $final = $rooms; }
                    }
                }
            }
            if ($final != -1){ $sql = mysql_query("UPDATE present SET rooms_id=$final WHERE player = $player AND items_id IS NULL AND monsters_id=$result;"); } 
            else { $sql = mysql_query("UPDATE present SET rooms_id=-1 WHERE player = $player AND items_id IS NULL AND monsters_id=$result");}
        }
    }
    $sql = mysql_query("UPDATE present SET state = 1 WHERE player = $player AND items_id IS NULL AND monsters_id IS NULL AND quantity IS NULL AND rooms_id IS NOT NULL");
} else {
    $sql = mysql_query("UPDATE present SET state = 0 WHERE player = $player AND items_id IS NULL AND monsters_id IS NULL AND quantity IS NULL AND rooms_id IS NOT NULL");
}

//成功的sql登录&$player已正确设置为“”，并且所有设置均低于sql
//语句执行正确$计数是2
功能设置怪物位置（$player，$rooms\u id）{
如果（mysql_结果（mysql_查询（“选择当前状态，其中player=$player和items_id为NULL，monsters_id为NULL，quantity为NULL，rooms_id不为NULL”），0）==0）{
$sql=mysql\u query（“从当前位置选择COUNT（*），其中player=$player和items\u id为空，monsters\u id>100，monsters\u id<300”）；
//注意这里我把$count改为$playerCount，因为它是一个
//玩家数量。
$playerCount=mysql\u结果（$sql，0）；
$sql=mysql\u query（“从当前位置选择怪物\u id，其中player=$player和items\u id为空，怪物\u id>100，怪物\u id<300，按怪物\u id排序”）；
对于（$i=0；$i<$playerCount；$i+=1）{
$sql=mysql\u query（“从当前位置选择怪物\u id，其中player=$player和items\u id为空，怪物\u id>100，怪物\u id<300，按怪物\u id排序”）；
$result=mysql\u结果（$sq）
// successful sql login & $player is correctly set with '', and all below sql
// statements execute correctly. $count is 2
function setMonstersLocation($player,$rooms_id){
if (mysql_result(mysql_query("SELECT state FROM present WHERE player = $player AND items_id IS NULL AND monsters_id IS NULL AND quantity IS NULL AND rooms_id IS NOT NULL"),0) == 0){
    $sql = mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id > 100 AND monsters_id < 300");
    // Note here I've changed $count to $playerCount, because it is a count of the
    // number of players.
    $playerCount = mysql_result($sql,0);
    $sql = mysql_query("SELECT monsters_id FROM present WHERE player = $player AND items_id IS NULL AND monsters_id > 100 AND monsters_id < 300 ORDER BY monsters_id");
    for ($i = 0; $i < $playerCount; $i+= 1) {
        $sql = mysql_query("SELECT monsters_id FROM present WHERE player = $player AND items_id IS NULL AND monsters_id > 100 AND monsters_id < 300 ORDER BY monsters_id");
        $result = mysql_result($sql,$i);
        if (mysql_result(mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id=$result AND quantity = 1"),0) == 1){
            $final = -1;
            $array[1] = $rooms_id - 1;
            $array[2] = $rooms_id + 1;
            $array[3] = $rooms_id - 100;
            $array[4] = $rooms_id + 100;
            $array[5] = $rooms_id - 200;
            $array[6] = $rooms_id - 101;
            $array[7] = $rooms_id - 99;
            $array[8] = $rooms_id - 2;
            $array[9] = $rooms_id + 200;
            $array[10] = $rooms_id + 101;
            $array[11] = $rooms_id + 99;
            $array[12] = $rooms_id + 2;
            if ($result < 200){
                for ($j = 1; $j < 5; $j+=1){
                    $sql = mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id IS NOT NULL AND rooms_id={$array[$j]}");
                    // Note here I've change $count to $presentCount, because you're
                    // counting the number of presents? (Whatever presents are)
                    $presentCount = mysql_result($sql,0);
                    $sql = mysql_query("SELECT COUNT(*) FROM rooms WHERE (rooms_id={$array[$j]})");
                    $roompresent = mysql_result($sql,0);
                    if ($presentCount == 0 and $final == -1 and $roompresent == 1){
                        $final = $array[$j];
                    }
                }
            } else if ($result > 200){
                for ($k = 1; $k < 13; $k+=1){
                    $sql = mysql_query("SELECT COUNT(*) FROM present WHERE (player = $player AND items_id IS NULL AND monsters_id IS NOT NULL AND rooms_id={$array[$k]})");
                    // You can use $presentCount again here, because it's a 
                    // different code block to the previous one.
                    // This doesn't mean its in a different SCOPE, however.
                    $presentCount = mysql_result($sql,0);
                    $sql = mysql_query("SELECT COUNT(*) FROM rooms WHERE (rooms_id={$array[$k]})");
                    $roompresent = mysql_result($sql,0);
                    if ($presentCount == 0 and $final == -1 and $roompresent == 1){ $final = $array[$k]; }
                }
                if ($final == -1){
                    $sql = mysql_query("SELECT COUNT(*) FROM rooms");
                    // Note here I've change $count to $roomsCount, because you're 
                    // counting the number of rooms.
                    $roomsCount = mysql_result($sql,0);
                    $sql = mysql_query("SELECT rooms_id FROM rooms");
                    for ($l = 0; $l < $roomsCount; $l+=1){
                        $rooms = mysql_query($sql,$l);
                        $sql = mysql_query("SELECT COUNT(*) FROM present WHERE player = $player AND items_id IS NULL AND monsters_id IS NOT NULL AND rooms_id=$rooms");
                        if (mysql_result($sql,0) == 0 and $final == -1){ $final = $rooms; }
                    }
                }
            }
            if ($final != -1){ $sql = mysql_query("UPDATE present SET rooms_id=$final WHERE player = $player AND items_id IS NULL AND monsters_id=$result;"); } 
            else { $sql = mysql_query("UPDATE present SET rooms_id=-1 WHERE player = $player AND items_id IS NULL AND monsters_id=$result");}
        }
    }
    $sql = mysql_query("UPDATE present SET state = 1 WHERE player = $player AND items_id IS NULL AND monsters_id IS NULL AND quantity IS NULL AND rooms_id IS NOT NULL");
} else {
    $sql = mysql_query("UPDATE present SET state = 0 WHERE player = $player AND items_id IS NULL AND monsters_id IS NULL AND quantity IS NULL AND rooms_id IS NOT NULL");
}