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Php 将数据库值除以10并更新web服务器_Php_Codeigniter_Webserver - Fatal编程技术网

Php 将数据库值除以10并更新web服务器

Php 将数据库值除以10并更新web服务器,php,codeigniter,webserver,Php,Codeigniter,Webserver,我为我们的网站找到了这段php代码,它将机器数据库中的机器值报告到网站上 function get_cycledata($serial) { $rows=array(); $this->db->select('cycle_timestamp,cycle_18_INT,cycle_03_INT,cycle_06_INT,cycle_08_INT,cycle_17_INT'); $this->db->from('cyc

我为我们的网站找到了这段php代码,它将机器数据库中的机器值报告到网站上

function get_cycledata($serial)
    { 
        $rows=array();
        $this->db->select('cycle_timestamp,cycle_18_INT,cycle_03_INT,cycle_06_INT,cycle_08_INT,cycle_17_INT');
        $this->db->from('cycles');
        $this->db->where('cycle_serial', $serial);
        $this->db->order_by("cycle_timestamp","desc"); 
        $q = $this->db->get();
        foreach($q->result_array() as $row)
        {
            $row['cycle_timestamp'] = $this->reports_model->time_convert($row['cycle_timestamp']);
            $rows[]=$row;
        }
        return $rows;   

    }

我想编辑值“cycle_06_INT”和“cycle_08_INT”,方法是将INT值除以10,然后将其显示在网站报告页面上。我该怎么做

您可以在选择列表中使用表达式:

$this->db->select('cycle_timestamp,cycle_18_INT,cycle_03_INT,cycle_06_INT/10,cycle_08_INT/10,cycle_17_INT');
# Here ------------------------------------------------------------------^-----------^

我试过了,但在重新加载页面时,它返回了一个错误:发生了数据库错误错误错误编号:1054“字段列表”中的未知列“cycle\u 06\u INT/10”,选择
cycle\u时间戳
cycle\u 18\u INT
cycle\u 03\u INT
cycle\u 06\u INT/10
cycle\u 08\u INT/10
cycle\u 17\u INT
FROM(
cycles
),其中
cycle\u serial
='0CSA000002'顺序按
cycle\u时间戳
desc文件名:models/reports\u model.php行号:63