Php 如何在MySQL数据库中找到前5个重复条目？

我正在尝试查找SQL表中重复行的最大数目。我可以获得计数，但数字会不时动态变化。那么我需要将计数添加到表中，然后找到计数列的最大值吗？或者我只需要找到计数列的最大值，而不将其添加到表中？我希望这些问题有意义。这是我到目前为止所拥有的

$countQuery = "SELECT breakers, COUNT(breakers) AS num FROM $tblEmerg GROUP BY breakers";
$count = mysqli_query($db, $countQuery) or die(mysqli_error($db));
    while($row = mysqli_fetch_assoc($count)){
        echo "<p>" .$row['breakers'] ." - " .$row['num'] ."</p>";
    }

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这正是我想要的，但正如我所提到的，“num”将动态变化，我只想返回前5个结果。我该怎么做呢？

您只需在查询中添加

按计数排序（断路器）DESC LIMIT 5

。

尝试以下操作：

SELECT breakers, COUNT(breakers) AS num 
  FROM $tblEmerg 
  GROUP BY breakers having num > 1 order by count(breakers) desc limit 5

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我想这会给你所要求的结果

SELECT breakers, COUNT(breakers) AS num FROM $tblEmerg GROUP BY breakers ORDER BY COUNT(breakers) DESC LIMIT 5

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添加订单编号和限额。例如，

ORDER BY num DESC LIMIT 5

Awesome。多谢各位much@Doon刚刚意识到你已经在评论中回答了：）干杯

SELECT breakers, COUNT(breakers) AS num FROM $tblEmerg GROUP BY breakers ORDER BY COUNT(breakers) DESC LIMIT 5