Php mysql-未知列在'；在/ALL/ANY子查询中'；

我有一个名为“投票”的下表，其中存储了参与者的向上投票（1）和向下投票（-1）。我想获得前三名投票参与者ID及其总投票数，其中总投票数=向上投票-向下投票。我编写了如下所示的查询，但出现错误：“in/ALL/ANY子查询”中的未知列“total_voces”

预期结果将是 ------------------------------- |参与者id |总票数| +------+-------+--------+------+ | 2 | 3 | 5 | 2 | 1 | 1 | 3 | 1 +------+-------+--------+------+

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由于您的表中没有

total_vows

列，您需要执行以下操作：

SELECT `participant_id`, SUM( `vote` ) AS total_votes FROM `votes` 
WHERE votes IN  
(SELECT total_votes FROM  
(SELECT DISTINCT (SUM( vote )) AS total_votes FROM  `votes` GROUP BY  `participant_id` 
ORDER BY `total_votes` DESC LIMIT 0 , 3) AS temp )  
GROUP BY `participant_id`

---

您可以使用join重新编写查询，以获取投票分数位于前三名投票中的前三名参与者，即前三名投票为（3,2,1）

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检查此简单查询：

SELECT 
participant_id, total_votes 
FROM 
(SELECT participant_id,SUM(vote) total_votes 
FROM votes 
GROUP BY participant_id) a 
ORDER BY total_votes DESC 
LIMIT 3;

要获得前三名投票的所有参与者，您可以使用以下查询：

SELECT 
a.participant_id, b.total_votes 
FROM 
(SELECT participant_id, SUM(vote) total_votes 
FROM votes 
GROUP BY participant_id) a 
JOIN 
(SELECT participant_id,SUM(vote) total_votes 
FROM votes 
GROUP BY participant_id 
ORDER BY total_votes DESC LIMIT 3) b
ON a.total_votes=b.total_votes 
ORDER BY total_votes DESC;

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@hardik如果参与者的分数与您的样本数据中的分数相同，则此查询将跳过id为3的参与者，尽管此参与者的投票分数也为top3s@MKhalidJunaid根据查询，他只需要前三名。@ZafarMalik查看他的问题和预期结果partright@khalid。。。你的答案很完美。。。我不想要前三名参与者的ID，而是前三名投票人，他们可能有相同的投票权……ok@hardik第二次查询将满足您的要求，我之前误解了您的要求。感谢khalid的反馈。这非常有效。。。只有我必须添加的是参与者ID的独特性。。。谢谢

SELECT `participant_id`, SUM( `vote` ) AS total_votes FROM `votes` 
WHERE votes IN  
(SELECT total_votes FROM  
(SELECT DISTINCT (SUM( vote )) AS total_votes FROM  `votes` GROUP BY  `participant_id` 
ORDER BY `total_votes` DESC LIMIT 0 , 3) AS temp )  
GROUP BY `participant_id`

SELECT t.* FROM
(SELECT `participant_id`, SUM( `vote` ) AS total_votes 
FROM `votes` 
GROUP BY `participant_id`
) t
JOIN  (SELECT SUM( `vote` ) AS total_votes FROM `votes` 
GROUP BY `participant_id`
ORDER BY `total_votes` DESC LIMIT 0 , 3 ) t1
USING(total_votes)
ORDER BY t.total_votes DESC

SELECT 
participant_id, total_votes 
FROM 
(SELECT participant_id,SUM(vote) total_votes 
FROM votes 
GROUP BY participant_id) a 
ORDER BY total_votes DESC 
LIMIT 3;

SELECT 
a.participant_id, b.total_votes 
FROM 
(SELECT participant_id, SUM(vote) total_votes 
FROM votes 
GROUP BY participant_id) a 
JOIN 
(SELECT participant_id,SUM(vote) total_votes 
FROM votes 
GROUP BY participant_id 
ORDER BY total_votes DESC LIMIT 3) b
ON a.total_votes=b.total_votes 
ORDER BY total_votes DESC;