Php SQLSTATE[42000]：语法错误或访问冲突：1064 laravel

在我的Laravel代码中，我使用

DB

访问数据库。在名为

showtheacherlist

的控制器函数中，我试图获取每位教师的所有作品。但是Laravel返回了这个错误。当我转储查询时，将其复制到

phpmyadmin

并运行，它就工作了。我的代码：

function showTeacherList($login){
    $select_result = DB::select('select id, name from kafedra where login = ?', [$login]);
    $kafedra_id = $select_result[0]->id;
    $teachers = DB::select('select id, name from teacher where kafedra_id = ?', [$kafedra_id]);
    $teacher_works = [];
    $i = 0;
    foreach ($teachers as $teacher) {
        $teacher_works[$i] = DB::select('select * from work where teacher_id = ?' [$teacher->id]);
        $i++;
    }
    return view('kafedra/teacher_list', ['login' => $login, 'name' => $select_result[0]->name, 'teachers' => $teachers, 'teacher_works' => $teacher_works]);
}

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请帮助，谢谢

您的

DB:：select

语句中有语法错误，特别是在

foreach

循环中。您遗漏了一个逗号，用于分隔

查询

和

绑定

替换：

$teacher_works[$i] = DB::select('select * from work where teacher_id = ?' [$teacher->id]);

与：

---

请提供完整准确的错误消息。

$teacher_works[$i] = DB::select('select * from work where teacher_id = ?', [$teacher->id]);