循环到数组中以使用PHP构建select

我在PHP中创建了以下数组：

$countries = array(
    array('CTY_Code' => 'AF', 'CTY_en' => 'Afghanistan', 'CTY_fr' => 'Afghanistan'),
    array('CTY_Code' => 'AL', 'CTY_en' => 'Albania', 'CTY_fr' => 'Albanie')
);

我如何循环到这一点，以进行如下选择：

<select>
    <option value='AF'>Afghanistan</option>
    <option value='AL'>Albania</option>
</select>

$countries = array(
    array('CTY_Code' => 'AF', 'CTY_en' => 'Afghanistan', 'CTY_fr' => 'Afghanistan'),
    array('CTY_Code' => 'AL', 'CTY_en' => 'Albania', 'CTY_fr' => 'Albanie')
);
echo sprintf(
    "<select>%s\n</select>",
    implode("", array_map(function ($value) {
        return sprintf("\n\t<option value=\"%s\">%s</option>", $value['CTY_Code'], $value['CTY_en']);
    }, $countries))
);

我尝试的是：

<select>
<?
foreach($CTY_Code as $key => $CTY_en) {
    echo '<option value="'.$CTY_Code.'">'.$CTY_en.'</option>';
}
?>
</select>

谢谢。

试试：

foreach ($countries as $key => $value) {
   echo '<option value="'.$value['CTY_Code'].'">'.$value['CTY_en'].'</option>';
}

你的阵列

$countries = array(
    array('CTY_Code' => 'AF', 'CTY_en' => 'Afghanistan', 'CTY_fr' => 'Afghanistan'),
    array('CTY_Code' => 'AL', 'CTY_en' => 'Albania', 'CTY_fr' => 'Albanie')
);

这是你的密码

echo "<select><option>--select country--</option>";
foreach ($countries as $countrykey => $countryvalue) {
        echo "<option value=".$countryvalue['CTY_Code'].">".$countryvalue['CTY_en']."</option>";
}
echo "</select>";

在html中使用php的另一种方法

<select><option>--select option--</option>
<?php foreach ($countries as $countrykey => $countryvalue) { ?>
    <option value="<?=$countryvalue['CTY_Code'];?>"><?=$countryvalue['CTY_en'];?></option>
<?php } ?>
</select>

试着这样做：

<select>
    <option value='AF'>Afghanistan</option>
    <option value='AL'>Albania</option>
</select>

$countries = array(
    array('CTY_Code' => 'AF', 'CTY_en' => 'Afghanistan', 'CTY_fr' => 'Afghanistan'),
    array('CTY_Code' => 'AL', 'CTY_en' => 'Albania', 'CTY_fr' => 'Albanie')
);
echo sprintf(
    "<select>%s\n</select>",
    implode("", array_map(function ($value) {
        return sprintf("\n\t<option value=\"%s\">%s</option>", $value['CTY_Code'], $value['CTY_en']);
    }, $countries))
);

这将给你：

<select>
    <option value="AF">Afghanistan</option>
    <option value="AL">Albania</option>
</select>

---

试试这个：foreach$countries为$arr{echo.$arr['CTY_en']。}你必须迭代$countries，而不是$CTY_代码，因为它根本不存在，然后从$arr的子数组中获取CTY_代码和CTY_en。我不明白为什么投票失败！问题清晰、格式良好、具体，显示了OP的努力