PHP正则表达式问题

我正在寻找一个人，可以帮助我与以下正则表达式

我有这个代码：我已经更新了它

<?php
$sitename = "http://" .$_SERVER["SERVER_NAME"];
$sitename = mysql_real_escape_string($sitename);
$language = "da";
$language = mysql_real_escape_string($language);
$pagename = $_SERVER["PHP_SELF"];
$pagename = mysql_real_escape_string($pagename);
$language1 = preg_replace("/$language/", "$1", "$pagename");
?>

---

由于$language变量中已经有了数据，所以应该发布一些真正的字符串来解析问题，这对您发布的代码没有什么意义。无论如何，在PHP中，您可以使用它将URL拆分为其组件，然后：

提取尾随字母（如果已修复） 并获得最后一个片段 具体细节取决于数据的外观

顺便说一句，您的JavaScript代码将/data/en更改为/sitenameta/en:-？

替换： 搜索：

   <?php
$sitename = "http://" .$_SERVER["SERVER_NAME"];
$sitename = mysql_real_escape_string($sitename);
$language = "\/da";
$pagename = $_SERVER["PHP_SELF"];
$pagename = mysql_real_escape_string($pagename);
$language1 = preg_replace("/$language/", "$1", "$pagename");
?>

 $language = mysql_real_escape_string($language);

$re = '/(?:\w+:\/\/[\w][\w.]+\/)(\w+)\//ui';
or this $re = '^(?:.*)\/(\w{2})\//ui';

$text = http://www.domain.com/ru/

preg_replace($re, 'ru', $text);

--> *http://www.domain.com/ru/*

$re = '/(?<domain>\w+:\/\/[\w][\w.]+\/)(?<lang>\w+)\//ui';
or this $re = '^(?:.*)\/(?<lang>\w{2})\//ui';

$text = http://www.domain.com/ru/

preg_match($re, $text, $aMatches);

--> Array
(
    [0] => http://www.domain.com/da/
    [domain] => http://www.domain.com/
    [1] => http://www.domain.com/
    [lang] => da
    [2] => da
)