Php 使用特定用户mgp25/instagram API获取我的instagram帖子

我正在使用mgp25/Instagram API

我怎样才能在instagram上找到像某个特定用户这样的帖子

我的代码：

set_time_limit(0);
date_default_timezone_set('UTC');
require __DIR__.'/vendor/autoload.php';

$username = 'myInstagramUsername';
$password = 'myInstagramPassword';
$debug = false;
$truncatedDebug = false;

$ig = new \InstagramAPI\Instagram($debug, $truncatedDebug);
try {
    $ig->login($username, $password);
} catch (\Exception $e) {
    echo 'Something went wrong: '.$e->getMessage()."\n";
    exit(0);
}
try {

    $userId = $ig->people->getUserIdForName($username);
    $act = json_encode($ig->people->getRecentActivityInbox(), true);
    ???????

} catch (\Exception $e) {
    echo 'Something went wrong: '.$e->getMessage()."\n";
}

---

尝试循环浏览你个人资料中的每个项目，然后找到喜欢的项目并找到用户名。然后，如果该用户将该项设置为like，则将其放入如下所示的项数组中：

// Get the UserPK ID for "natgeo" (National Geographic).
$userId = $ig->people->getUserIdForName('natgeo');
// Starting at "null" means starting at the first page.
$maxId = null;
do {

    $response = $ig->timeline->getUserFeed($userId, $maxId);
    // In this example we're simply printing the IDs of this page's items.
    foreach ($response->getItems() as $item) {
       //loop through likes as u can see in [source 1][1] there is some method called 'getLikers()' which u can call on a media object.
        foreach($item->getMedia()->getLikers() as $h){
            // here do some if with if response user == username
        }
    }

资料来源1： 资料来源2： 资料来源3：

---

通过读取源文件，这可能会起作用，但我尚未对其进行测试。

起作用。

set_time_limit(0);
date_default_timezone_set('UTC');
require __DIR__.'/vendor/autoload.php';

$username = 'username';
$password = 'password';
$debug = false;
$truncatedDebug = false;


$ig = new \InstagramAPI\Instagram($debug, $truncatedDebug);
try {
    $ig->login($username, $password);
} catch (\Exception $e) {
    echo 'Something went wrong: '.$e->getMessage()."\n";
    exit(0);
}
try {

    $posts = [];
    $comments = [];

    $userId = $ig->people->getUserIdForName($username);
    $maxId = null;

        $response = $ig->timeline->getUserFeed($userId, $maxId);
        foreach ($response->getItems() as $item) {
            foreach($item->getLikers($item->getId()) as $h){
                $posts[] = ['id' => $item->getId(), 'username' => $h->username];
            }

            foreach($ig->media->getComments($item->getId()) as $v){             
                if(count($v->comments) > 0){
                    foreach($v->comments as $c){
                        $comments[] = ['id' => $item->getId(), 'username' => $c->user->username, 'text' => $c->text];
                    }
                }
            }

        }

        print_r($posts);
        print_r($comments);

} catch (\Exception $e) {
    echo 'Something went wrong: '.$e->getMessage()."\n";
}

---

对于mgp25的新版本，此代码可以正常工作

更新后

$likes = [];
$comments = [];
$userId = $ig->people->getUserIdForName($username);
$maxId = null;
$response = $ig->timeline->getUserFeed($userId, $maxId);
$posts = $response->jsonSerialize();
foreach ($response->getItems() as $item) {
    $likers = $ig->media->getLikers($item->getId());
    if ($likers != null) {
        foreach ($likers->getUsers() as $h) {
            $likes[] = ['id' => $item->getId(), 'username' => $h->getUsername()];
        }
    }
    $commentsList = $ig->media->getComments($item->getId());
    if ($commentsList != null) {
        foreach ($commentsList->getComments() as $c) {
            $comments[] = ['id' => $item->getId(), 'username' => $c->getUser()->getUsername(), 'text' => $c->getText()];
        }
    }
}

---

但是这个函数getRecentActivityInbox（）返回的是什么呢？它返回的ActivityNewsResponse可以在这里找到：不是

foreach（$item->getMedia（）->>getLikers（）作为$h）

，而是

foreach（$item->getLikers（$item->getId（））作为$h）

。但是

$item->getComments（$item->getId（））

不起作用。有什么想法吗？