Php 从数据库中获取值并在数组中显示结果
我有一张像这样的购物车桌子Php 从数据库中获取值并在数组中显示结果,php,mysql,sql,arrays,mysqli,Php,Mysql,Sql,Arrays,Mysqli,我有一张像这样的购物车桌子 id catid catname userid productid prodimg prodname prodsize prodcost quantity datee timee totalamount 1 1 CN1 1 1 ABC P1 small 10 1 3/10/2015 10:00a
id catid catname userid productid prodimg prodname prodsize prodcost quantity datee timee totalamount
1 1 CN1 1 1 ABC P1 small 10 1 3/10/2015 10:00am 10
2 1 CN1 1 1 ABC P1 medium 20 1 4/10/2015 10:00am 20
3 1 CN1 1 1 ABC P1 large 30 1 3/10/2015 10:00am 30
4 1 CN1 1 1 ABC P1 perpiece 5 1 3/10/2015 10:00am 5
5 1 CN1 1 2 CDF P2 small 6 1 3/10/2015 10:00am 6
6 1 CN1 1 2 CDF P2 large 14 1 4/10/2015 10:00am 14
7 1 CN1 2 1 ABC P1 small 10 2 3/10/2015 10:00am 20
我希望以一种特定的方式在数组中显示它的数据(根据userid),我想要的结果数组如下所示
Array
(
[0] => Array
(
[catid] => 1
[catname] => CN1
[userid] => 1
[productid] => 1
[prodimg] => ABC
[prodname] => P1
[prodsize] => Array
(
[0] => small
[1] => medium
[2] => large
[3] => perpiece
)
[prodcost] => Array
(
[0] => 10
[1] => 20
[2] => 30
[3] => 5
)
[quantity] => Array
(
[0] => 1
[1] => 1
[2] => 1
[3] => 1
)
[datee] => Array
(
[0] => 3/10/2015
[1] => 4/10/2015
[2] => 3/10/2015
[3] => 3/10/2015
)
[timee] => Array
(
[0] => 10:00am
[1] => 10:00am
[2] => 10:00am
[3] => 10:00am
)
[totalamount] => Array
(
[0] => 10
[1] => 20
[2] => 30
[3] => 5
)
)
[1] => Array
(
[catid] => 1
[catname] => CN1
[userid] => 1
[productid] => 2
[prodimg] => CDF
[prodname] => P2
[prodsize] => Array
(
[0] => small
[1] => 0
[2] => large
[3] => 0
)
[prodcost] => Array
(
[0] => 6
[1] => 0
[2] => 14
[3] => 0
)
[quantity] => Array
(
[0] => 1
[1] => 0
[2] => 1
[3] => 0
)
[datee] => Array
(
[0] => 3/10/2015
[1] => 0
[2] => 4/10/2015
[3] => 0
)
[timee] => Array
(
[0] => 10:00am
[1] => 0
[2] => 10:00am
[3] => 0
)
[totalamount] => Array
(
[0] => 6
[1] => 0
[2] => 14
[3] => 0
)
)
)
我使用的代码是
$userid = $_REQUEST['userid'];
$sql= "SELECT catid, catname, productid, prodimg, GROUP_CONCAT(prodsize ORDER BY id ASC) as prodsize, GROUP_CONCAT(prodcost ORDER BY id ASC) as prodcost, GROUP_CONCAT(quantity ORDER BY id ASC) as quantity, GROUP_CONCAT(datee ORDER BY id ASC) as datee, GROUP_CONCAT(timee ORDER BY id ASC) as timee,
GROUP_CONCAT(totalamount ORDER BY id ASC) as totalamount from cart WHERE userid ='$userid'";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0)
{
while($result = mysqli_fetch_assoc($result))
{
echo "<pre>";
print_r($result);
echo "</pre>";
}
}
谁能告诉我如何以正确的方式获取阵列。该数组的另一个重要方面是,prodsize中的数组应该是固定的,即如果prod大小较小,则它将存储在[0]、[1]中、[2]中的较大值和[3]中的每件中,如果其中一个值不存在,则它应该是0,并且prodcost,quantity Date和timee也将遵循相同的方法来获取数组中sql select查询的所有结果,只需使用下面的fetch all函数
$formatedResult = [];
$i = 0;
while($result = mysqli_fetch_assoc($result))
{
$formatedResult = $result;
$formatedResult[$i]['prodsize'] = explode(',', $result[$i]['prodsize']);
$formatedResult[$i]['prodcost'] = explode(',', $result[$i]['prodcost']);
$formatedResult[$i]['quantity'] = explode(',', $result[$i]['quantity']);
$formatedResult[$i]['datee'] = explode(',', $result[$i]['datee']);
$formatedResult[$i]['timee'] = explode(',', $result[$i]['timee']);
$formatedResult[$i]['totalamount'] = explode(',', $result[$i]['totalamount']);
//Repeat with the other elements with similar formating
$i++;
}
echo '<pre>';
print_r($formatedResult); //Now shows the array you want
echo '</pre>';
我认为您需要一种算法来重新格式化数据库中的结果。我可以看到你想要的就是得到那些连接的结果,并用独立的数组键将它们分开 我还没有尝试过,但我怀疑您可能需要也可能不需要$I索引来分配元素。两种都试试 以下是一种实现此目标的方法:
$formattedResult=[];
$i=0;
而($result=mysqli\u fetch\u assoc($result))
{
$FormattedResult=$result;
$formattedResult[$i]['prodsize']=分解(',',$result[$i]['prodsize']);
$formattedResult[$i]['prodcost']=explode(',',$result[$i]['prodcost']);
$FormattedResult[$i]['quantity']=分解(',',$result[$i]['quantity']);
$formattedResult[$i]['datee']=分解(',',$result[$i]['datee']);
$formattedResult[$i]['timee']=分解(',',$result[$i]['timee']);
$FormattedResult[$i]['totalamount']=分解(',',$result[$i]['totalamount']);
//对具有类似格式的其他元素重复此操作
$i++;
}
回声';
Array
(
[0] => Array
(
[catid] => 1
[catname] => CN1
[productid] => 1
[prodimg] => ABC
[prodsize] => small,medium,large
[prodcost] => 10,20,30
[quantity] => 1,1,1,1
[datee] => 3/10/2015,4/10/2015,3/10/2015,3/10/2015
[timee] => 10:00am,10:00am,10:00am,10:00am
[totalamount] => 10,20,30,5
)
)
打印(FormattedResult)//现在显示所需的阵列
回声';
Array
(
[0] => Array
(
[catid] => 1
[catname] => CN1
[productid] => 1
[prodimg] => ABC
[prodsize] => small,medium,large
[prodcost] => 10,20,30
[quantity] => 1,1,1,1
[datee] => 3/10/2015,4/10/2015,3/10/2015,3/10/2015
[timee] => 10:00am,10:00am,10:00am,10:00am
[totalamount] => 10,20,30,5
)
)
它以什么方式不起作用?结果如何?SQL错误?数组的格式不符合您的要求?但它不起作用。是否有任何错误/意外结果?是否尝试确保查询没有失败echo$sql=“选择catid、catname、productid、prodimg、GROUP_CONCAT(按id排序的prodsize ORDER ASC)作为prodsize,GROUP_CONCAT(按id排序的prodcost ORDER ASC)作为prodcost,GROUP_CONCAT(按id排序的DATE ORDER ASC)作为datee,GROUP__CONCAT(按id排序的TIME ORDER ASC)作为timee,GROUP_CONCAT(totalamount ORDER BY id ASC)作为来自购物车的totalamount,其中userid='$userid''
你看到了什么?@Juan Bonnett没有出现错误,但数组的获取方式与我的不同wanted@HawasKaPujaari查询没有失败,但我没有按照我想要的方式获取数组。请在phpmyadmin或任何其他MySQL环境中执行查询,并向我们显示结果?它只提供了用户添加的1个产品的详细信息,但我我已经更新了我的帖子,当你的查询返回所有三行时,你可以在mysql控制台或phpMyAdmin上检查它
Array
(
[0] => Array
(
[catid] => 1
[catname] => CN1
[productid] => 1
[prodimg] => ABC
[prodsize] => small,medium,large
[prodcost] => 10,20,30
[quantity] => 1,1,1,1
[datee] => 3/10/2015,4/10/2015,3/10/2015,3/10/2015
[timee] => 10:00am,10:00am,10:00am,10:00am
[totalamount] => 10,20,30,5
)
)