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Php 如何使用codeigniter中的sendgrid api库作为第三方库_Php_Codeigniter_Email_Sendgrid - Fatal编程技术网

Php 如何使用codeigniter中的sendgrid api库作为第三方库

Php 如何使用codeigniter中的sendgrid api库作为第三方库,php,codeigniter,email,sendgrid,Php,Codeigniter,Email,Sendgrid,如何在codeigniter中将sendgrid库用作第三方。 在他们的网站上,我可以找到扩展普通codeigniter电子邮件类的smtp代码。 有什么帮助吗 <?php $this->load->library('email'); $this->email->initialize(array( 'protocol' => 'smtp', 'smtp_host' => 'smtp.sendgrid.net', 'smtp_user' =&

如何在codeigniter中将sendgrid库用作第三方。 在他们的网站上,我可以找到扩展普通codeigniter电子邮件类的smtp代码。 有什么帮助吗

<?php
$this->load->library('email');

$this->email->initialize(array(
  'protocol' => 'smtp',
  'smtp_host' => 'smtp.sendgrid.net',
  'smtp_user' => 'sendgridusername',
  'smtp_pass' => 'sendgridpassword',
  'smtp_port' => 587,
  'crlf' => "\r\n",
  'newline' => "\r\n"
));

$this->email->from('your@example.com', 'Your Name');
$this->email->to('someoneexampexample@example.com');
$this->email->cc('another@another-example.com');
$this->email->bcc('them@their-example.com');
$this->email->subject('Email Test');
$this->email->message('Testing the email class.');
$this->email->send();

echo $this->email->print_debugger();
?>

步骤1:将sendgrid库复制到第三方文件夹 步骤2:将以下代码添加到控制器方法

include APPPATH . 'third_party/sendgrid-php/sendgrid-php.php';

        //$this->load->third_party('sendgrid-php');



        $email = new \SendGrid\Mail\Mail();
        $email->setFrom("setfrom@test.com", "testname");
        $email->setSubject("MailTest");
        $email->addTo('tomail@gmail.com', "User");
        $email->addContent("text/plain", "subject");
        $email->addContent(
            "text/html",'<html><body>Message</body><html>');

        $sendgrid = new \SendGrid(('sendgrid-API-KEY_HERE'));
        try {
            $response = $sendgrid->send($email);
            print $response->statusCode() . "\n";
            print_r($response->headers());
            print $response->body() . "\n";
        } catch (Exception $e) {
            echo 'Caught exception: '. $e->getMessage() ."\n";
        }
包括应用路径。”第三方/sendgrid php/sendgrid php.php';
//$this->load->third_party('sendgrid-php');
$email=new\SendGrid\Mail\Mail();
$email->setFrom(“setfrom@test.com“,”测试名称“);
$email->setSubject(“MailTest”);
$email->addTo($email)tomail@gmail.com","用户";;
$email->addContent(“文本/普通”、“主题”);
$email->addContent(
“文本/html”、“消息”);
$sendgrid=new\sendgrid(('sendgrid-API-KEY_HERE');
试一试{
$response=$sendgrid->send($email);
打印$response->statusCode()。“\n”;
打印($response->headers());
打印$response->body()。“\n”;
}捕获(例外$e){
回显“捕获的异常:”。$e->getMessage()。“\n”;
}
希望能奏效