在回音中创建带有回音的php if语句

大家早上好，我正在尝试做下面的工作，这样如果类型不是“main”，区域名称就会在li中重复出现。然而，它只是输出字符串中的内容，有没有一种方法可以成功地实现这一点，并节省我创建800英尺页面的时间

        <?php if ($type=="main" ) {
                echo '
                <ul class="footer-nav">
                <h2>Links</h2>
                <li><a href="index.php">Home</a></li>
                <li><a href="services.php">Our Services</a></li>
                <li><a href="upvc.php">Upvc repairs</a></li>
                <li><a href="emergency.php">Emergency 24/7</a></li>
              </ul>';}
              else
                echo '
                <ul class="footer-nav">
                <h2>Links</h2>
                <li><a href="locksmiths-<?php echo $areaname ?>.php">Home</a></li>
                <li><a href="services-<?php echo $areaname ?>.php">Our Services</a></li>
                <li><a href="services-upvc-repairs-<?php echo $area-name ?>.php">Upvc repairs</a></li>
                <li><a href="services-<?php echo $area-name ?>-24hour.php">Emergency 24/7</a></li>
              </ul>'
  ?>

---

这应该可以解决您的问题。 你忘了做一个适当的陈述

        <?php if ($type=="main" ) {
            echo '
            <ul class="footer-nav">
            <h2>Links</h2>
            <li><a href="index.php">Home</a></li>
            <li><a href="services.php">Our Services</a></li>
            <li><a href="upvc.php">Upvc repairs</a></li>
            <li><a href="emergency.php">Emergency 24/7</a></li>
          </ul>';}
          else {
            echo '
            <ul class="footer-nav">
            <h2>Links</h2>
            <li><a href="locksmiths-'.$areaname.'.php">Home</a></li>
            <li><a href="services-'.$areaname.'.php">Our Services</a></li>
            <li><a href="services-upvc-repairs-'.$areaname.'.php">Upvc repairs</a></li>
            <li><a href="services-'.$areaname.'-24hour.php">Emergency 24/7</a></li>
          </ul>';}
?>

---

您有一些语法错误，请这样使用

<?php if ($type=="main" ) {
                echo '
                <ul class="footer-nav">
                <h2>Links</h2>
                <li><a href="index.php">Home</a></li>
                <li><a href="services.php">Our Services</a></li>
                <li><a href="upvc.php">Upvc repairs</a></li>
                <li><a href="emergency.php">Emergency 24/7</a></li>
              </ul>';
            }else{
                echo '
                <ul class="footer-nav">
                <h2>Links</h2>
                <li><a href="locksmiths-'.$areaname.'.php">Home</a></li>
                <li><a href="services-'.$areaname.'.php">Our Services</a></li>
                <li><a href="services-upvc-repairs-'.$areaname.'.php">Upvc repairs</a></li>
                <li><a href="services-'.$areaname.'-24hour.php">Emergency 24/7</a></li>
              </ul>';
            }
  ?>

---

确保变量名，如我将

$area name

替换为

$areaname

无需将echo放入echo中。。请遵循以下更改

<?php if ($type=="main" ) :
            echo '
            <ul class="footer-nav">
            <h2>Links</h2>
            <li><a href="index.php">Home</a></li>
            <li><a href="services.php">Our Services</a></li>
            <li><a href="upvc.php">Upvc repairs</a></li>
            <li><a href="emergency.php">Emergency 24/7</a></li>
          </ul>';
          else:
            echo '
            <ul class="footer-nav">
            <h2>Links</h2>
            <li><a href="locksmiths-'.$areaname.'.php">Home</a></li>
            <li><a href="services-.'$areaname.'.php">Our Services</a></li>
            <li><a href="services-upvc-repairs-.'$area-name.'.php">Upvc repairs</a></li>
            <li><a href="services-'.$area-name.'-24hour.php">Emergency 24/7</a></li>
          </ul>'
    endif;?>

---

您可以用HTML编写php代码，而不必使用双引号，如下所示：

<?php if ($type == "main"): ?>
    <ul class="footer-nav">
         <h2>Links</h2>
         <li><a href="index.php">Home</a></li>
         <li><a href="services.php">Our Services</a></li>
         <li><a href="upvc.php">Upvc repairs</a></li>
         <li><a href="emergency.php">Emergency 24/7</a></li>
     </ul>
<?php else: ?>
    <ul class="footer-nav">
        <h2>Links</h2>
        <li><a href="locksmiths-<?= $areaname ?>.php">Home</a></li>
        <li><a href="services-<?= $areaname ?>.php">Our Services</a></li>
        <li><a href="services-upvc-repairs-<?= $area-name ?>.php">Upvc repairs</a></li>
        <li><a href="services-<?= $area-name ?>-24hour.php">Emergency 24/7</a></li>
    </ul>
<?php endif; ?>

链接






链接

最短的代码

像我一样，您只能回显一次公共数据

变量

$area name

无效。。。我将其转换为$area\u名称

<?php 
    echo '<ul class="footer-nav"><h2>Links</h2>'; //common data
if ($type=="main")
    echo '
        <li><a href="index.php">Home</a></li>
        <li><a href="services.php">Our Services</a></li>
        <li><a href="upvc.php">Upvc repairs</a></li>
        <li><a href="emergency.php">Emergency 24/7</a></li>';
else echo '
        <li><a href="locksmiths-'.$areaname.'.php">Home</a></li>
        <li><a href="services-'.$areaname.'.php">Our Services</a></li>
        <li><a href="services-upvc-repairs-'.$area_name.'.php">Upvc repairs</a></li>
        <li><a href="services-'.$area_name.'-24hour.php">Emergency 24/7</a></li>';
echo '</ul>';//common data
?>

$area name
是无效的变量名，可能是输入错误

看到你的html，我建议你浏览一下


下面是另一种提高可读性的方法，首先删除
echo

<?php if ($type=="main" ): ?>
              <ul class="footer-nav">
                <h2>Links</h2>
                <li><a href="index.php">Home</a></li>
                <li><a href="services.php">Our Services</a></li>
                <li><a href="upvc.php">Upvc repairs</a></li>
                <li><a href="emergency.php">Emergency 24/7</a></li>
              </ul>
<?php else: ?>
              <ul class="footer-nav">
                <h2>Links</h2>
                <li><a href="locksmiths-<?php echo $areaname; ?>.php">Home</a></li>
                <li><a href="services-<?php echo $areaname; ?>.php">Our Services</a></li>
                <li><a href="services-upvc-repairs-<?php echo $areaname; ?>.php">Upvc repairs</a></li>
                <li><a href="services-<?php echo $areaname; ?>-24hour.php">Emergency 24/7</a></li>
              </ul>
<?php endif;?>



链接






链接





更好的方法是使用三元运算符，这样您就不需要重复HTML，只需更改链接：

<ul class="footer-nav">
    <h2>Links</h2>
    <li><a href="<?= ($type == "main" ? 'index.php' :     'locksmiths-'.$areaname.'.php') ?>">Home</a></li>
    <li><a href="<?= ($type == "main" ? 'services.php' :  'services-'.$areaname.'.php') ?>">Our Services</a></li>
    <li><a href="<?= ($type == "main" ? 'upvc.php' :      'services-upvc-repairs-'.$areaname.'.php') ?>">Upvc repairs</a></li>
    <li><a href="<?= ($type == "main" ? 'emergency.php' : 'services-'.$areaname.'-24hour.php') ?>">Emergency 24/7</a></li>
</ul>


链接






或者，您可能希望将HTML中的数据提取到一个数组中，这将使添加更多链接或使链接更具动态性（在数据库中）更加容易

<?php
$links = [
    [
        'name' => 'Home',
        'main' => 'index.php',
        'area' => 'locksmiths-'.$areaname.'.php'
    ], [
        'name' => 'Our Services',
        'main' => 'services.php',
        'area' => 'services-'.$areaname.'.php'
    ], [
        'name' => 'Upvc repairs',
        'main' => 'upvc.php',
        'area' => 'services-upvc-repairs-'.$areaname.'.php'
    ], [
        'name' => 'Emergency 24/7',
        'main' => 'emergency.php',
        'area' => 'services-'.$areaname.'-24hour.php'
    ],
];
?>
<ul class="footer-nav">
    <h2>Links</h2>
    <?php foreach ($links as $link): ?>
    <li><a href="<?= ($type == "main" ? $link['main'] : $link['area']) ?>"><?= $link['name'] ?></a></li>
    <?php endforeach ?>
</ul>



链接


$areaname='wales'；
$pages=[
'index.php'=>'Home'，
'services.php'=>'我们的服务'，
'upvc.php'=>'upvc修复'，
'emergency.php'=>'emergency 24/7'
];
$area\U URL=[
“锁匠-$areaname.php”，
“服务-$areaname.php”，
“服务upvc修复-$areaname.php”，
“服务-$areaname-24hour.php”
];
如果（$type！=“main”）
$pages=array\u combine（$area\u url，$pages）；
//输出菜单
回显“链接\n
\n”；
foreach（$link=>$page的页面）
printf（“\t
\n”，$link，$page）；
回声“
\n”；
比其他答案更清晰，但怀疑它是否符合OP的要求。@sakuto，我猜他无法评估echo的其他部分。我想这应该对他有帮助。没有测试它！它的
type==main
不是
type==mail
谢谢大家这么快的回复！我认为h2是ul的直系子是无效的html。很容易，获胜者：）我只能投一个作为正确答案，尽管他们是，这是我使用的答案
$areaname = 'wales';
$pages = [
    'index.php' => 'Home',
    'services.php' => 'Our Services',
    'upvc.php' => 'Upvc repairs',
    'emergency.php' => 'Emergency 24/7'
];
$area_urls = [
    "locksmiths-$areaname.php",
    "services-$areaname.php",
    "services-upvc-repairs-$areaname.php",
    "services-$areaname-24hour.php"
];
if($type != 'main')
    $pages = array_combine($area_urls, $pages);
// Output menu
echo "<h2>Links</h2>\n<ul class='footer-nav'>\n";
    foreach($pages as $link => $page)
        printf("\t<li><a href='%s'>%s</a></li>\n", $link, $page);
echo "</ul>\n";