Php 选择更好的结果匹配

我有一个小问题需要解决。我需要搜索更好的结果

我有三张表，规则，意思和规则的意思。1规则可以有1个或多个含义

这是我们的结果

SELECT * FROM rule, rule_meaning, meaning WHERE rule_meaning.rule_id = rule.id AND rule_meaning.meaning_id = meaning.i

rule.id rule.name   rule.id meaning_id  meaning.id  meaning.name
1   RADIO - Ecouter   1        1          1          ACTIVER
1   RADIO - Ecouter   1        6          6          RADIO
2   LUMIERE Allumer   2        1          1          ACTIVER
3   RADIO + volume    3        6          6          RADIO
4   RADIO - volume    4        6          6          RADIO

当我搜索ACTIVER和RADIO时，我只希望有RADIO-Ecouter（rule.id=1）

我试过了

• 其中，meaning.name=ACTIVER和meaning.name=RADIO，但没有结果

• 其中meaning.name=ACTIVER或meaning.name=RADIO我有几个结果

---

您可能需要使用案例陈述，例如

    CASE WHEN WHERE meaning.name = ACTIVER AND meaning.name = RADIO
    THEN ....
    ELSE

但我想你问的是

    WHERE meaning.name = ACTIVER AND rule.name = RADIO 
    AND rule.id = 1

---

您希望选择同时具有ACTIVER和RADIO含义的规则。您可以通过聚合执行此操作：

select *
from rule
where id in
(
  select rule_id
  from rule_meaning 
  where meaning_id in (select id from meaning where name in ('ACTIVER', 'RADIO'))
  group by rule_id
  having count(*) = 2 -- both meanings
);

我不太喜欢的另一种方法是使用

EXISTS

或

IN

分别查找每个值。我在这里展示它是因为它是完成任务的简单方法

select *
from rule
where id in
(
  select rule_id
  from rule_meaning 
  where meaning_id = (select id from meaning where name = 'ACTIVER')
)
and id in
(
  select rule_id
  from rule_meaning 
  where meaning_id = (select id from meaning where name = 'RADIO')
);

---

你会犯什么错误？有什么问题吗

meaning.name=ACTIVER和meaning.name=RADIO

没有任何意义…任何东西怎么可能同时有两个值请在格式化文本（而不是图像）中共享您的模式和预期结果事实上，我只想选择与这两个词ACTIVER和RADIO同时匹配的结果。这就是为什么我说结果必须是规则。id 1这是唯一的