为PHP中上载的每个图像的表图像提供ads_id

我有一些简单的表单供用户上传广告，如下所示：

正如你所看到的，有一个图片表单，用户可以在他们的广告中放置多张图片

我有一张表格，上面有图像，如下所示：

正如您可以看到的那样，ads\u id列始终为0，我没有找到一种方法来为每个上传的图像放置ads\u id

广告表格如下所示：

下面是我用来执行操作的uploader.php文件：

<?php
// Define variables and initialize with empty values
$title = $status = $category = $location = $description = $mark = $notes = $user_id =  "";
$statusMsg = $errorMsg = $insertValuesSQL = $errorUpload = $errorUploadType = '';

if(isset($_POST['submit'])){

// Include the database configuration file
include 'session.php';

// File upload configuration
$targetDir = "upload/";
$allowTypes = array('jpg','png','jpeg','gif');

//giving a value
$title = $_POST["title"];
$status = $_POST["status"];
$category = $_POST["category"];
$location = $_POST["location"];
$description = $_POST["description"];
$mark = $_POST["mark"];
$notes = $_POST["notes"];
$user_id = $_SESSION["user_id"];

mysqli_query($koneksi, "INSERT INTO ads(user_id,category_id,status,title,location,mark,description,notes,date_posted) VALUES ('$user_id', '$category','$status', '$title','$location', '$mark','$description', '$notes',NOW())");
//images uploader
if(!empty(array_filter($_FILES['images']['name']))){
    foreach($_FILES['images']['name'] as $key=>$val){
        // File upload path
        $fileName = basename($_FILES['images']['name'][$key]);
        $targetFilePath = $targetDir . $fileName;

        // Check whether file type is valid
        $fileType = pathinfo($targetFilePath,PATHINFO_EXTENSION);
        if(in_array($fileType, $allowTypes)){
            // Upload file to server
            if(move_uploaded_file($_FILES["images"]["tmp_name"][$key], $targetFilePath)){
                // Image db insert sql
                $insertValuesSQL .= "('".$fileName."', NOW()),";
            }else{
                $errorUpload .= $_FILES['images']['name'][$key].', ';
            }
        }else{
            $errorUploadType .= $_FILES['images']['name'][$key].', ';
        }
    }

    if(!empty($insertValuesSQL)){
        $insertValuesSQL = trim($insertValuesSQL,',');
        // Insert image file name into database
        $insert = $koneksi->query("INSERT INTO images (file_name, uploaded_on) VALUES $insertValuesSQL");
        if($insert){
            $errorUpload = !empty($errorUpload)?'Upload Error: '.$errorUpload:'';
            $errorUploadType = !empty($errorUploadType)?'File Type Error: '.$errorUploadType:'';
            $errorMsg = !empty($errorUpload)?'<br/>'.$errorUpload.'<br/>'.$errorUploadType:'<br/>'.$errorUploadType;
            $statusMsg = "Files are uploaded successfully.".$errorMsg;
        }else{
            $statusMsg = "Sorry, there was an error uploading your file.";
        }
    }
}else{
    $statusMsg = 'Please select a file to upload.';
}

// Display status message
echo $statusMsg;
header('refresh:1; url=index.php');
}
?>

---

首先，您应该将更新查询添加到脚本中，最好在
if（$insert）{
之后进行此操作，以获取您可以使用的最后一个插入ID，如Carl所述，示例如下：

if($insert){
    $last_inserted_id = $insert->insert_id;
    $update_ads_id = $koneksi->query("UPDATE images SET ads_id = 2"); // or what id you want.

注意：您应该学习如何使用
实现更多安全脚本。首先，您应该在脚本中添加更新查询，最好在
if（$insert）{
之后进行此操作，以获取您可以使用的最后一个插入ID，如Carl所述，示例如下：

if($insert){
    $last_inserted_id = $insert->insert_id;
    $update_ads_id = $koneksi->query("UPDATE images SET ads_id = 2"); // or what id you want.

注意：您应该学习如何使用
实现更多安全脚本。您需要获取最后插入的记录的id，然后使用它。您可以执行以下操作：

if (mysqli_query($koneksi, "INSERT INTO ads(user_id,category_id,status,title,location,mark,description,notes,date_posted) VALUES ('$user_id', '$category','$status', '$title','$location', '$mark','$description', '$notes',NOW())")) {
    $last_id = mysqli_insert_id($koneksi); // now you can insert this with rest of your data to your images table...
}

您需要获取最后插入的记录的id，然后使用它。您可以执行以下操作：

if (mysqli_query($koneksi, "INSERT INTO ads(user_id,category_id,status,title,location,mark,description,notes,date_posted) VALUES ('$user_id', '$category','$status', '$title','$location', '$mark','$description', '$notes',NOW())")) {
    $last_id = mysqli_insert_id($koneksi); // now you can insert this with rest of your data to your images table...
}

感谢Morgan、Saud和Carl，mysqli\u insert\u id（）就是答案

最后，我在第一次查询后放置了最后插入的\u id，这样它就得到了最新的广告id

mysqli_query($koneksi, "INSERT INTO ads(user_id,category_id,status,title,location,mark,description,notes,date_posted) VALUES ('$user_id', '$category','$status', '$title','$location', '$mark','$description', '$notes',NOW())");
$last_inserted_id = $insert->insert_id;

之后，我将其插入到图像查询中

$insertValuesSQL .= "('$last_inserted_id','".$fileName."', NOW()),";
$insert = $koneksi->query("INSERT INTO images (ads_id,file_name, uploaded_on) VALUES $insertValuesSQL");

感谢Morgan、Saud和Carl，mysqli\u insert\u id（）就是答案

最后，我在第一次查询后放置了最后插入的\u id，这样它就得到了最新的广告id

mysqli_query($koneksi, "INSERT INTO ads(user_id,category_id,status,title,location,mark,description,notes,date_posted) VALUES ('$user_id', '$category','$status', '$title','$location', '$mark','$description', '$notes',NOW())");
$last_inserted_id = $insert->insert_id;

之后，我将其插入到图像查询中

$insertValuesSQL .= "('$last_inserted_id','".$fileName."', NOW()),";
$insert = $koneksi->query("INSERT INTO images (ads_id,file_name, uploaded_on) VALUES $insertValuesSQL");

您需要获取最后一个插入查询的id，就像使用我只是对mysqli_insert_id（）进行一些研究，这正是我所需要的。感谢您的帮助！您需要获取最后一个插入查询的id，就像使用我只是对mysqli_insert_id（）进行一些研究，这正是我所需要的。谢谢您的帮助！