Php 面包屑从下拉菜单mysql
mysql中有三个表组成了下拉菜单,如下代码所示。 我想从这个菜单中得到一个带链接的$breadcrumb变量。例如: 家庭/妇女 家/女人/衣服 家/女人/衣服/女人T恤-2 有可能吗Php 面包屑从下拉菜单mysql,php,mysql,menu,dropdown,breadcrumbs,Php,Mysql,Menu,Dropdown,Breadcrumbs,mysql中有三个表组成了下拉菜单,如下代码所示。 我想从这个菜单中得到一个带链接的$breadcrumb变量。例如: 家庭/妇女 家/女人/衣服 家/女人/衣服/女人T恤-2 有可能吗 <div id="sitemaps" class="menu"> <ul> <li><a href="index.p
<div id="sitemaps" class="menu">
<ul>
<li><a href="index.php">Home</a></li>
<?php
$statement = $pdo->prepare("SELECT * FROM tbl_top_category WHERE show_on_menu=1");
$statement->execute();
$result = $statement->fetchAll(PDO::FETCH_ASSOC);
foreach ($result as $row) {
?>
<li><a href="product-category.php?id=<?php echo $row['tcat_id']; ?>&type=top-category"><?php echo $row['tcat_name']; ?></a>
<ul>
<?php
$statement1 = $pdo->prepare("SELECT * FROM tbl_mid_category WHERE tcat_id=?");
$statement1->execute(array($row['tcat_id']));
$result1 = $statement1->fetchAll(PDO::FETCH_ASSOC);
foreach ($result1 as $row1) {
?>
<li><a href="product-category.php?id=<?php echo $row1['mcat_id']; ?>&type=mid-category"><?php echo $row1['mcat_name']; ?></a>
<ul>
<?php
$statement2 = $pdo->prepare("SELECT * FROM tbl_end_category WHERE mcat_id=?");
$statement2->execute(array($row1['mcat_id']));
$result2 = $statement2->fetchAll(PDO::FETCH_ASSOC);
foreach ($result2 as $row2) {
?>
<li><a href="product-category.php?id=<?php echo $row2['ecat_id']; ?>&type=end-category"><?php echo $row2['ecat_name']; ?></a></li>
<?php
}
?>
</ul>
</li>
<?php
}
?>
</ul>
</li>
<?php
}
?>
<div class="breadcrumb" style="margin-top:20px"><a href="<?php echo BASE_URL; ?>">Home / </a> <?php echo $breadcrumb ?>
</div>
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