Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/php/286.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Yii框架显示了一个充满原始php代码的页面_Php_Zend Framework_Yii - Fatal编程技术网

Yii框架显示了一个充满原始php代码的页面

Yii框架显示了一个充满原始php代码的页面,php,zend-framework,yii,Php,Zend Framework,Yii,在Yii项目中,我的导航菜单定义如下: <?php $this->widget('zii.widgets.CMenu', array( 'items' => array( array('label' => 'Home', 'url' => array('/index.php/site/index')), array('label' => 'Users', 'url' => array('/index.php/use

在Yii项目中,我的导航菜单定义如下:

<?php
$this->widget('zii.widgets.CMenu', array(
    'items' => array(
        array('label' => 'Home', 'url' => array('/index.php/site/index')),
        array('label' => 'Users', 'url' => array('/index.php/user/user/index'),'visible' =>  Yii::app()->user->hasRole('admin')),
        array('label' => 'Pages', 'url' => array('/index.php/pages/index'),'visible' =>  Yii::app()->user->hasRole('admin')),
        array('label' => 'About', 'url' => array('/index.php/site/page', 'view' => 'about')),
        array('label' => 'Contact', 'url' => array('/index.php/site/contact')),
        array('label' => 'Login', 'url' => array('/index.php/user/login'), 'visible' => Yii::app()->user->isGuest),
        array('label' => 'Logout (' . Yii::app()->user->name . ')', 'url' => array('/index.php/user/auth/logout'), 'visible' => !Yii::app()->user->isGuest)
    ),
));
?>

当我点击登录链接时,它返回我


如何修复登录页面?

这可能就是原因

检查您的
index.php
main.php
或具有
short\u open\u标记的任何其他控制器或模型文件,即