Php 从上传的文件中读取

我用这个代码上传一个文本文件

<?php

if(isset($_POST['submit'])){
$name = $_FILES["file"]["name"];

$tmp_name = $_FILES['file']['tmp_name'];
$error = $_FILES['file']['error'];

if (isset ($name)) {
    if (!empty($name)) {

    $location = 'C:/inetpub/wwwroot/';

    if  (move_uploaded_file($tmp_name, $location.$name)){
        echo 'File Uploaded';    
        }

        } else {
          echo 'please choose a file';
          }
    }
}
?>

<form action="" method="POST" enctype="multipart/form-data">
    <input type="file" name="file"><br><br>
    <input type="submit" name="submit" value="Submit">
</form>

然后我有这个代码来逐行读取文件的内容

<?php

    $lines = file ('the_name_of_file.txt');
    foreach ($lines as $name){
        echo "$name <br>";

    }

?>

---

如何使用第二个代码读取上载的文件？

要读取已上载的文件，需要读取上载到的目录

<?php
    $location = 'C:/inetpub/wwwroot/';
    $lines = file($location . 'the_name_of_file.txt');
    foreach ($lines as $name) {
        // Code here
    }
?>

if（移动上传的文件（$tmp\u name，$location.$name））{
$lines=文件（$location.$name）；
foreach（$行作为$name）{
回显“$name
”；
}
}

使用

fopen

读取本地文件

$lines=file（$\u files['file']['tmp\u name']）
if  (move_uploaded_file($tmp_name, $location.$name)){
     $lines = file ($location.$name);
     foreach ($lines as $name){
       echo "$name <br>";

    }
  }