如果未找到，php循环将显示当前年份数据，而不是跳过_Php_Loops_Foreach

如果未找到，php循环将显示当前年份数据，而不是跳过

php loops

如果未找到，php循环将显示当前年份数据，而不是跳过,php,loops,foreach,Php,Loops,Foreach,因此，我在一个循环中有一个循环，两个循环都有年份数据，我试图找出如果年份不匹配或循环中不存在年份，如何显示当前年份（2021年）数据，而不是使用“继续”跳过条目，任何想法或解决方案都值得赞赏实时代码：这就是我得到的输出： Array ( [0] => Array ( [year] => 2021 [price] => 255 ) ) Array ( ) Array ( [0]

因此，我在一个循环中有一个循环，两个循环都有年份数据，我试图找出如果年份不匹配或循环中不存在年份，如何显示当前年份（2021年）数据，而不是使用“继续”跳过条目，任何想法或解决方案都值得赞赏

实时代码：

这就是我得到的输出：

Array
(
    [0] => Array
        (
            [year] => 2021
            [price] => 255
        )

)
Array
(
)
Array
(
    [0] => Array
        (
            [year] => 2023
            [price] => 300
        )

)

这就是我想要的结果：

Array
(
    [0] => Array
        (
            [year] => 2021
            [price] => 255
        )

)
Array
(
    [0] => Array
        (
            [year] => 2021
            [price] => 255
        )

)
Array
(
    [0] => Array
        (
            [year] => 2023
            [price] => 300
        )

)

试试这个

    $dates = [
    ['date_starts'=>'2021-03-22'],
    ['date_starts'=>'2022-04-22'],
    ['date_starts'=>'2023-05-22']
];
              
foreach( $dates as $dt ){
    $start_date = $dt['date_starts'];
    
    $rates_results = [
        ['price'=>255,'year'=>'2021'],
        ['price'=>300,'year'=>'2022'],
        ['price'=>300,'year'=>'2023']
    ];

    $rateIDs = [];
    if ($rates_results) {
        foreach ($rates_results as $rates) {
            if(date("Y", strtotime($start_date)) !== ''.$rates['year'].''){
             
                continue;
                
            }
           
                $rateIDs [] = [
                'year' => $rates['year'],
                'price' => $rates['price']
            ];
            
            
           
        }
    }
    print_r($rateIDs);
}

试试这个

    $dates = [
    ['date_starts'=>'2021-03-22'],
    ['date_starts'=>'2022-04-22'],
    ['date_starts'=>'2023-05-22']
];
              
foreach( $dates as $dt ){
    $start_date = $dt['date_starts'];
    
    $rates_results = [
        ['price'=>255,'year'=>'2021'],
        ['price'=>300,'year'=>'2022'],
        ['price'=>300,'year'=>'2023']
    ];

    $rateIDs = [];
    if ($rates_results) {
        foreach ($rates_results as $rates) {
            if(date("Y", strtotime($start_date)) !== ''.$rates['year'].''){
             
                continue;
                
            }
           
                $rateIDs [] = [
                'year' => $rates['year'],
                'price' => $rates['price']
            ];
            
            
           
        }
    }
    print_r($rateIDs);
}

我不确定我是否理解正确，但接下来

在循环之前初始化

$matched

变量，如果存在匹配项，则将其设置为

true

（以知道不需要添加当前年份数据）

如果没有匹配项，请搜索数据数组（

$rates\u results

）以查看当前年份是否存在，如果存在，请将其添加到结果中

<?php
$dates = [
    ['date_starts'=>'2021-03-22'],
    ['date_starts'=>'2022-04-22'],
    ['date_starts'=>'2023-05-22']
];
              
foreach( $dates as $dt ){
    $start_date = $dt['date_starts'];
    
    $rates_results = [
        ['price'=>255,'year'=>'2021'],
        ['price'=>300,'year'=>'2023']
    ];

    $rateIDs = [];
    if ($rates_results) {
        $matched = false;
        
        foreach ($rates_results as $rates) {
            if(date("Y", strtotime($start_date)) !== ''.$rates['year'].'') {
                continue;
            }
            
            $matched = true;
            $rateIDs[] = [
                'year' => $rates['year'],
                'price' => $rates['price']
            ];
        }
        
        if ($matched === false) {
            $key = array_search(date('Y'), array_column($rates_results, 'year'));
            if ($key !== false) {
                $rateIDs[] = [
                    'year' => $rates_results[$key]['year'],
                    'price' => $rates_results[$key]['price']
                ];
            }
        }
    }
    print_r($rateIDs);
}