Php Yii，自定义WebUser属性

好吧，我做得对

用户身份

class UserIdentity extends CUserIdentity
{
    const ERROR_NOT_ACTIVE = 111;
    //
    private $role;
    private $_id;

    /**
     * @return bool
     */
    public function authenticate()
    {
        $oUser = User::model()->find('LOWER(login) = ?', array(strtolower($this->username)));

        if ($oUser === null) {
            $this->errorCode = self::ERROR_USERNAME_INVALID;
        } else {
            // wrong password
            if (!$oUser->validatePassword($this->password)) {
                $this->errorCode = self::ERROR_PASSWORD_INVALID;
            } // user not activated by admin
            elseif ($oUser->active) {
                $this->_id = $oUser->id;
                $this->role = $oUser->role;
                $this->username = $oUser->login;
                $this->errorCode = self::ERROR_NONE;
            } // user valid and activated
            else {
                $this->errorCode = self::ERROR_NOT_ACTIVE;
            }
        }

        return $this->errorCode == self::ERROR_NONE;
    }

    /**
     * @return mixed|string
     */
    public function getID()
    {
        return $this->_id;
    }

    public function getRole()
    {
        return $this->role;
    }
}

网络用户

class WebUser extends CWebUser
{
    /**
     * @return boolean
     */
    public function isAdmin()
    {
        var_dump($this->getState('role'));
        return ($this->getState('role') === User::ROLE_ADMIN);
    }
}

配置

'components' => array(
        'user' => array(
            // enable cookie-based authentication
            'class' => 'WebUser',

---

但是在WebUser中根本没有角色属性。任何其他的变化都会导致错误。问题是如何从UserIdentity（登录时一次）向WebUser提供任何数据，但不使用对db（在WebUser中）的额外查询

在您的用户标识中，而不是：

$this->role = $oUser->role;

这样做：

$this->setState('role',$oUser->role);

您还可以从顶部删除

private$role