PHP递归迭代器-反转和计数结果
我有以下资料:PHP递归迭代器-反转和计数结果,php,object,count,reverse,Php,Object,Count,Reverse,我有以下资料: <?php $path = '/home/user/test'; $dir = new RecursiveDirectoryIterator( $path ); $iterator = new RecursiveIteratorIterator( $dir ); $dir_iterator = new RegexIterator( $iterator, '/^.+\.php/i', RecursiveRegexIterator::GET_MATCH ); ?>
<?php
$path = '/home/user/test';
$dir = new RecursiveDirectoryIterator( $path );
$iterator = new RecursiveIteratorIterator( $dir );
$dir_iterator = new RegexIterator( $iterator, '/^.+\.php/i', RecursiveRegexIterator::GET_MATCH );
?>
到目前为止还不错,但我需要反转结果,以归档与array_reverse()相同的效果
我这样试过,但没有成功:
<?php
$dir_iterator = array_reverse( (array)$dir_iterator );
?>
另外,如何获得返回的结果数?我试过这个,但不起作用:
<?php
$total_results = count( $dir_iterator );
?>
有人能帮我吗
非常感谢 你需要的是
迭代器到数组
你可以试试
$dir_iterator = array_reverse(iterator_to_array($dir_iterator ));
要计算迭代器,您需要:
$total_results = iterator_count( $dir_iterator );
最好是你的
$dir_iterator = new ReverseIterator($dir_iterator);
foreach ( $dir_iterator as $file ) {
// do your thing
}
// To get total
echo count($dir_iterator);
使用的类
class ReverseIterator extends ArrayIterator implements Countable {
private $t;
public function __construct(Iterator $it) {
$r = array_reverse(iterator_to_array($it));
$this->t = count($r);
parent::__construct($r);
unset($r);
}
function count() {
return $this->t;
}
}
太棒了,就是这样!非常感谢你!不客气。。有关可使用的可重用代码,请参见更新的代码