Php 在一个查询中计算两个字段的问题

伙计们，我需要统计一下新的和旧的私人信息

所以首先想到的是使用mysql_num_行和简单的操作

  // check new pms
  $user_id  = $userinfo['user_id'];
  $sql = "SELECT author_id  FROM bb3privmsgs_to WHERE user_id='$user_id' AND (pm_new='1' OR  pm_unread='1')";
  $result = $db->sql_query($sql) ;
  $new_pms = $db->sql_numrows($result);
  $db->sql_freeresult($result);

  // check old pms
  $sql = "SELECT author_id  FROM bb3privmsgs_to WHERE user_id='$user_id' AND (pm_new='0' OR  pm_unread='0')";
  $result = $db->sql_query($sql) ;
  $old_pms = $db->sql_numrows($result);
  $db->sql_freeresult($result);

---

但是如何在一条语句和更短的行中计算这两个字段呢？~

使用此查询：

SELECT SUM(CASE WHEN pm_new = '1' OR pm_unread = '1' THEN 1 ELSE 0 END) AS new_pms,
       SUM(CASE WHEN pm_new = '0' OR pm_unread = '0' THEN 1 ELSE 0 END) AS old_pms
  FROM bb3privmsgs_to
 WHERE user_id='$user_id'

下面是一个MySQL特定的版本，它读起来更清晰：

SELECT COUNT(IF(pm_new = '1' OR pm_unread = '1', 1, NULL)) AS new_pms,
       COUNT(IF(pm_new = '0' OR pm_unread = '0', 1, NULL)) AS old_pms
  FROM bb3privmsgs_to
 WHERE user_id='$user_id'

---

在SQL Server中，您可以执行以下操作：

SELECT 
   SUM(CASE WHEN pm_new='1' OR  pm_unread='1' THEN 1 ELSE 0 END),
   SUM(CASE WHEN pm_new='0' OR  pm_unread='0' THEN 1 ELSE 0 END) 
FROM 
   bb3privmsgs_to WHERE user_id='$user_id'

---

我想你也可以在mySql中做同样的事情，让我再告诉你细节…

mySql将对1或0进行比较。您可以使用

SUM（）

将您试图计算结果的

WHERE

子句的部分相加

这是一个（特定于MySQL的）较短的替代方案，用于

示例时的
情况

SELECT 
  SUM(pm_new='1' OR pm_unread='1') as new_pms, 
  SUM(pm_new='0' OR pm_unread='0') as old_pms
FROM bb3privmsgs_to
WHERE user_id='$userid'

作为其他一些建议的替代方案：

SELECT SUM(newPMS) AS newPMS,
       SUM(oldPMS) AS oldPMS
  FROM ( SELECT COUNT(author_id) AS newPMS,
                0 AS oldPMS
           FROM bb3privmsgs_to
          WHERE user_id='$user_id'
            AND (pm_new='1' OR pm_unread='1')
         UNION
         SELECT 0 AS newPMS
                COUNT(author_id) AS oldPMS
           FROM bb3privmsgs_to
          WHERE user_id='$user_id'
            AND (pm_new='0' OR pm_unread='0')
       )