PHP数组对象集合问题

我有以下PHP代码：

class SQLStatements {
    public function __construct($iName) {
        $this->name = $iName;
        $this->sqlStatement = array ();
    }

    public function addStatement($iSQLStatement) {
        $this->sqlStatement [] = $iSQLStatement;
    }

...other functions...
}

print_r ($ss);
$sqlStatements->addStatement ( $ss );   
print_r ($sqlStatements);

输出为：

SQLStatement Object ( [id] => 300 [timestamp] => 201301090222 [fixture] => Home v Away [outcome] => Home [fixtureDateTime] => 2013-01-11 [bookmakerOdds] => Array ( [0] => 2.15 [1] => 2.22 [2] => 2.05 [3] => 2.05 [4] => 2.15 [5] => 2.20 [6] => 2.14 ) ) SQLStatements Object ( [name] => TheStatement [sqlStatement] => Array ( [0] => SQLStatement Object ( [id] => 300 [timestamp] => 201301090222 [fixture] => Home v Away [outcome] => Home [fixtureDateTime] => 2013-01-11 [bookmakerOdds] => Array ( [0] => 2.15 [1] => 2.22 [2] => 2.05 [3] => 2.05 [4] => 2.15 [5] => 2.20 [6] => 2.14 ) ) ) ) SQLStatement Object ( [id] => 300 [timestamp] => 201301090222 [fixture] => Home v Away [outcome] => Home v Away - Draw [fixtureDateTime] => 2013-01-11 [bookmakerOdds] => Array ( [0] => 3.50 [1] => 3.50 [2] => 3.40 [3] => 3.40 [4] => 3.30 [5] => 3.50 [6] => 3.28 ) ) SQLStatements Object ( [name] => TheStatement [sqlStatement] => Array ( [0] => SQLStatement Object ( [id] => 300 [timestamp] => 201301090222 [fixture] => Home v Away [outcome] => Home v Away - Draw [fixtureDateTime] => 2013-01-11 [bookmakerOdds] => Array ( [0] => 3.50 [1] => 3.50 [2] => 3.40 [3] => 3.40 [4] => 3.30 [5] => 3.50 [6] => 3.28 ) ) [1] => SQLStatement Object ( [id] => 300 [timestamp] => 201301090222 [fixture] => Home v Away [outcome] => Home v Away - Draw [fixtureDateTime] => 2013-01-11 [bookmakerOdds] => Array ( [0] => 3.50 [1] => 3.50 [2] => 3.40 [3] => 3.40 [4] => 3.30 [5] => 3.50 [6] => 3.28 ) ) ) ) SQLStatement对象 ( [id]=>300 [时间戳]=>201301090222 [固定装置]=>主场v客场 [结果]=>主页 [fixtureDateTime]=>2013-01-11 [BookMakerRods]=>数组 ( [0] => 2.15 [1] => 2.22 [2] => 2.05 [3] => 2.05 [4] => 2.15 [5] => 2.20 [6] => 2.14 ) ) SQLStatements对象 ( [名称]=>声明 [sqlStatement]=>数组 ( [0]=>SQLStatement对象 ( [id]=>300 [时间戳]=>201301090222 [固定装置]=>主场v客场 [结果]=>主页 [fixtureDateTime]=>2013-01-11 [BookMakerRods]=>数组 ( [0] => 2.15 [1] => 2.22 [2] => 2.05 [3] => 2.05 [4] => 2.15 [5] => 2.20 [6] => 2.14 ) ) ) ) SQLStatement对象 ( [id]=>300 [时间戳]=>201301090222 [固定装置]=>主场v客场 [结果]=>主客场-平局 [fixtureDateTime]=>2013-01-11 [BookMakerRods]=>数组 ( [0] => 3.50 [1] => 3.50 [2] => 3.40 [3] => 3.40 [4] => 3.30 [5] => 3.50 [6] => 3.28 ) ) SQLStatements对象 ( [名称]=>声明 [sqlStatement]=>数组 ( [0]=>SQLStatement对象 ( [id]=>300 [时间戳]=>201301090222 [固定装置]=>主场v客场 [结果]=>主客场-平局 [fixtureDateTime]=>2013-01-11 [BookMakerRods]=>数组 ( [0] => 3.50 [1] => 3.50 [2] => 3.40 [3] => 3.40 [4] => 3.30 [5] => 3.50 [6] => 3.28 ) ) [1] =>SQLStatement对象 ( [id]=>300 [时间戳]=>201301090222 [固定装置]=>主场v客场 [结果]=>主客场-平局 [fixtureDateTime]=>2013-01-11 [BookMakerRods]=>数组 ( [0] => 3.50 [1] => 3.50 [2] => 3.40 [3] => 3.40 [4] => 3.30 [5] => 3.50 [6] => 3.28 ) ) ) )

---

$ss

是

SQLStatement

对象，而

SQLStatements

对象是

SQLStatement

对象的集合。但是，从输出中可以看到，SQLStatements->SQLStatement[0]和SQLStatements->SQLStatement[1]是相同的。我希望SQLStatements->SQLStatement[0]->结果是“Home”，而不是“Home v Away-Draw”。我做错了什么？

当一个对象被传递给PHP中的一个方法时，PHP实际上会在内存中传递该对象地址的值。这意味着，当您调用

addStatement（$ss）

时，您并没有将

$ss

对象的副本添加到statements数组中，而是在内存中添加指向该对象的指针。如果以后更改

$ss

对象，它也将在SQLStatements类中的数组中更改（因为它们指向内存中的同一对象）

---

您应该做的是，在调用

addStatement（$ss）

之后，您应该执行如下操作：

$ss=new SQLStatement（）

和，然后可以进行更改并再次添加它（通过创建

新SQLStatement（））

您已为此新对象分配了另一个内存块，并且该位置有一个新的内存地址，该地址不会与分配给

$ss

的旧对象冲突）

请显示用于添加两个对象的完整代码（可能是循环？）。这就是答案。谢谢你，科林。