Php 无法访问同一类上的方法

我不理解这方面的逻辑，我得到一个错误，我的函数convertBinToMSSQLGuid找不到。我知道编码没有意义，只是为了测试。也试着把它保密，没有运气

class PowerBiResource extends JsonResource
{
    /**
     * Transform the resource into an array.
     *
     * @param  \Illuminate\Http\Request  $request
     * @return array
     */
    public function toArray($request)
    {
       dd(convertBinToMSSQLGuid($this->VehicleID));
       return '';
    }
    public function convertBinToMSSQLGuid($binguid)
    {
       $unpacked = unpack('Va/v2b/n2c/Nd',$binguid);
       return sprintf('%08X-%04X-%04X-%04X-%04X%08X', $unpacked['a'], $unpacked['b1'], $unpacked['b2'], $unpacked['c1'], $unpacked['c2'], $unpacked['d']);
    }
}

当您从其类内部调用convertBinToMSSQLGuid时，必须使用$this->：

---

不能通过直接名称直接访问任何自定义类函数。您可以通过以下方式访问：

class PowerBiResource extends JsonResource
{
    /**
     * Transform the resource into an array.
     *
     * @param  \Illuminate\Http\Request  $request
     * @return array
     */
    public function toArray($request)
    {
       dd($this->convertBinToMSSQLGuid($this->VehicleID));
       return '';
    }
    public function convertBinToMSSQLGuid($binguid)
    {
       $unpacked = unpack('Va/v2b/n2c/Nd',$binguid);
       return sprintf('%08X-%04X-%04X-%04X-%04X%08X', $unpacked['a'], $unpacked['b1'], $unpacked['b2'], $unpacked['c1'], $unpacked['c2'], $unpacked['d']);
    }
}

您可以通过引用$this->来使用该函数。希望对你有帮助

class PowerBiResource extends JsonResource
{
    /**
     * Transform the resource into an array.
     *
     * @param  \Illuminate\Http\Request  $request
     * @return array
     */
    public function toArray($request)
    {
       dd($this->convertBinToMSSQLGuid($this->VehicleID));
       return '';
    }
    public function convertBinToMSSQLGuid($binguid)
    {
       $unpacked = unpack('Va/v2b/n2c/Nd',$binguid);
       return sprintf('%08X-%04X-%04X-%04X-%04X%08X', $unpacked['a'], $unpacked['b1'], $unpacked['b2'], $unpacked['c1'], $unpacked['c2'], $unpacked['d']);
    }
}