Php HTML列表视图表单提交正确,但mysql db使用顺序未正确显示HTML
HTML代码:Php HTML列表视图表单提交正确,但mysql db使用顺序未正确显示HTML,php,html,mysql,Php,Html,Mysql,HTML代码: <form action="addbook.php" method="post"> <select name="sort"> <option value="FirstName">Firstname</option> <option value="LastName">Lastname</option> <option value="State">State</option> &l
<form action="addbook.php" method="post">
<select name="sort">
<option value="FirstName">Firstname</option>
<option value="LastName">Lastname</option>
<option value="State">State</option>
<option value="City">City</option>
</select>
<input type="submit" value="Sort">
</form>
同样在使用chrome的开发模式下,post变量存在,列表提交似乎工作正常。请检查给出结果的查询和不给出结果的查询是否相同。当您将变量用于“order by”时,可能会出现单引号/双引号的问题。请通过打印两个查询进行检查。这是单引号。有趣的东西。谢谢。您可以通过以下方式轻松获得:“$sort@user2781617”从联系人订单中选择*您是说您的问题已解决,还是您已经尝试过我的解决方案,对您的问题没有任何帮助。你最后的评论我不清楚。萨蒂什:“$sort”的意义是什么?
if(isset($_POST['sort'])){
echo "true";
if($_POST['sort']=="FirstName"){
$sort="FirstName";
}
else if($_POST['sort']=="LastName"){
$sort="LastName";
}
else if($_POST['sort']=="City"){
$sort="City";
}
else if($_POST['sort']=="State"){
$sort="State";
}
}
$result=mysqli_query($con, "SELECT * FROM Contact ORDER BY $sort");
echo "<table border='1'>
<tr>
<th>Lastname</th>
<th>Firstname</th>
<th>Address</th>
<th>City</th>
<th>State</th>
</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['City'] . "</td>";
echo "<td>" . $row['State'] . "</td>";
echo "</tr>";
}
echo "</table>";
Connected to MySQL
Lastname Firstname Address City State