Php 如果没有发布，如何不更新_Php

Php 如果没有发布，如何不更新

php

Php 如果没有发布，如何不更新,php,Php,我有以下标准形式：表格： <div id="ajaXmsg"></div> <form method="post" accept-charset="UTF-8" action="#" class="formee" id="useredit"/> <input type="hidden" name="p" id="p" value=""> <input type="hidden" name="retype" i

我有以下标准形式：

表格：

                <div id="ajaXmsg"></div>
<form method="post" accept-charset="UTF-8" action="#" class="formee" id="useredit"/>
<input type="hidden" name="p" id="p" value="">
<input type="hidden" name="retype" id="retype" value="">
<input type="hidden" name="oldpass" id="oldpass" value="">
<?php $n->generateFormFields(); ?>
<table style="margin:0 auto;width:100%">
        <tr>

            <td style="font-weight:bold;">שינוי שם משתמש (נוכחי <span style="color:blue;"><?php echo $user['username']; ?></span>) ל - </td>
            <td>
                <input style="height:30px;width:250px;padding:0;line-height:30px;" type="text" id="uname" name="uname" value="" placeholder="<?php echo $user['username']; ?>" class="inplaceError" /><span class="clear" id="uname_error"></span>
            </td>
        </tr>
        <tr>
            <td style="font-weight:bold;">שינוי שם פרטי (נוכחי <span style="color:blue;"><?php echo $user['user_fname']; ?></span>) ל - </td>
            <td><input type="text" id="fname" value="" placeholder="<?php echo $user['user_fname']; ?>" name="fname" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;" /><span class="clear" id="fname_error"></span></td>
        </tr>
                <tr>
            <td style="font-weight:bold;">
שינוי שם משפחה(נוכחי <span style="color:blue;"><?php echo $user['user_lname']; ?></span>) ל - </td>
            <td><input type="text" id="lname" value="" placeholder="<?php echo $user['user_lname']; ?>" name="fname" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;" /><span class="clear" id="lname_error"></span></td>
        </tr>
        <tr>
            <td style="font-weight:bold;">שינוי דוא"ל (נוכחי <span style="color:blue;"><?php echo $user['useremail']; ?></span>) ל - </td>
            <td><input type="text" id="email" value="" placeholder="<?php echo $user['useremail']; ?>" name="email" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;" /> <span class="clear" id="email_error"></span></td>
        </tr>
        <tr>
            <td style="font-weight:bold;">שינוי סיסמא:</td>
            <td><input type="password" id="password"  name="password" style="height:30px;width:250px;padding:0;"/><span style="color:black;font-weight:bold;" class="inplaceError"> *הקש שנית: </span><input type="password" id="newpass"  onclick="this.value='';" name="newpass" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;"/><span class="clear" id="password_error"></span><span class="clear" id="newpass_error"></span></td>
        </tr>
<tr>
            <td style="font-weight:bold;">*סיסמא נוכחית:</td>
            <td><input type="password" id="oldpassinp" name="oldpassinp" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;"/> 
            <span class="clear" id="oldpassinp_error" ></span>
            </td>
        </tr>
        <tr>
            <td></td>
            <td><a href="#" id="submitedit" onClick="return false;" style="text-decoration:none;"><div class="editbut">עדכן</div></a></td>
        </tr>
    </table>

</form>

        if ($update_stmt = $func->mysqli->prepare(

        "UPDATE users SET 
           username = ?,
           useremail = ?,
           user_fname = ?,
           user_lname = ?,
           timestamp = ?,
           password = ?, 
           salt = ? 
           WHERE userid = '".$user_data['userid']."'"

        ))
        {

        $update_stmt->bind_param('sssssss',$uname, $useremail,$user_fname,$user_lname,$timestamp, $password, $random_salt);
        // Execute the prepared query.
        $update_stmt->execute();
            $return = array('form' => true,'key' => $json['2'], 'nonce' => $json['1']);
             header('content-type: application/json; charset=utf-8');
             echo json_encode($return);

        }
        else
        {
               $return = array('form' => false,'key' => $json['2'], 'nonce' => $json['1']);
                header('content-type: application/json; charset=utf-8');
               echo json_encode($return);

        }

 username=(CASE username WHEN '".empty($_POST['uname'])."' THEN username ELSE ? END),

现在我通过ajax发送，所有工作都完美执行一件事：

即使字段（post）为空，它也会将字段更新为空，这不好，我需要保留相同的字段而不进行更新，我的意思是，如果字段为空，则不更新所有特定列，我该怎么做
例如：
如果post用户名为空，则不更新所有用户名列
提前感谢，如果需要，将添加更多代码
编辑1:

<div id="ajaXmsg"></div> <form method="post" accept-charset="UTF-8" action="#" class="formee" id="useredit"/> <input type="hidden" name="p" id="p" value=""> <input type="hidden" name="retype" id="retype" value=""> <input type="hidden" name="oldpass" id="oldpass" value=""> <?php $n->generateFormFields(); ?> <table style="margin:0 auto;width:100%"> <tr> <td style="font-weight:bold;">שינוי שם משתמש (נוכחי <span style="color:blue;"><?php echo $user['username']; ?></span>) ל - </td> <td> <input style="height:30px;width:250px;padding:0;line-height:30px;" type="text" id="uname" name="uname" value="" placeholder="<?php echo $user['username']; ?>" class="inplaceError" /><span class="clear" id="uname_error"></span> </td> </tr> <tr> <td style="font-weight:bold;">שינוי שם פרטי (נוכחי <span style="color:blue;"><?php echo $user['user_fname']; ?></span>) ל - </td> <td><input type="text" id="fname" value="" placeholder="<?php echo $user['user_fname']; ?>" name="fname" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;" /><span class="clear" id="fname_error"></span></td> </tr> <tr> <td style="font-weight:bold;"> שינוי שם משפחה(נוכחי <span style="color:blue;"><?php echo $user['user_lname']; ?></span>) ל - </td> <td><input type="text" id="lname" value="" placeholder="<?php echo $user['user_lname']; ?>" name="fname" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;" /><span class="clear" id="lname_error"></span></td> </tr> <tr> <td style="font-weight:bold;">שינוי דוא"ל (נוכחי <span style="color:blue;"><?php echo $user['useremail']; ?></span>) ל - </td> <td><input type="text" id="email" value="" placeholder="<?php echo $user['useremail']; ?>" name="email" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;" /> <span class="clear" id="email_error"></span></td> </tr> <tr> <td style="font-weight:bold;">שינוי סיסמא:</td> <td><input type="password" id="password" name="password" style="height:30px;width:250px;padding:0;"/><span style="color:black;font-weight:bold;" class="inplaceError"> *הקש שנית: </span><input type="password" id="newpass" onclick="this.value='';" name="newpass" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;"/><span class="clear" id="password_error"></span><span class="clear" id="newpass_error"></span></td> </tr> <tr> <td style="font-weight:bold;">*סיסמא נוכחית:</td> <td><input type="password" id="oldpassinp" name="oldpassinp" class="inplaceError" style="height:30px;width:250px;padding:0;line-height:30px;"/> <span class="clear" id="oldpassinp_error" ></span> </td> </tr> <tr> <td></td> <td><a href="#" id="submitedit" onClick="return false;" style="text-decoration:none;"><div class="editbut">עדכן</div></a></td> </tr> </table> </form>

if ($update_stmt = $func->mysqli->prepare( "UPDATE users SET username = ?, useremail = ?, user_fname = ?, user_lname = ?, timestamp = ?, password = ?, salt = ? WHERE userid = '".$user_data['userid']."'" )) { $update_stmt->bind_param('sssssss',$uname, $useremail,$user_fname,$user_lname,$timestamp, $password, $random_salt); // Execute the prepared query. $update_stmt->execute(); $return = array('form' => true,'key' => $json['2'], 'nonce' => $json['1']); header('content-type: application/json; charset=utf-8'); echo json_encode($return); } else { $return = array('form' => false,'key' => $json['2'], 'nonce' => $json['1']); header('content-type: application/json; charset=utf-8'); echo json_encode($return); }

username=(CASE username WHEN '".empty($_POST['uname'])."' THEN username ELSE ? END),
这就是你的意思吗？
在查询中使用mysql

UPDATE tablename SET column1 = CASE WHEN phppostvalue = '' THEN column1 ELSE ? END WHERE someconditions
查询中可以有多个条件，例如

UPDATE tablename SET column1 = CASE WHEN phppostvalue = '' THEN column1 ELSE ? END, SET column1 = CASE WHEN phppostvalue = '' THEN column1 ELSE ? END, SET column1 = CASE WHEN phppostvalue = '' THEN column1 ELSE ? END WHERE someconditions
使用PHP：

$buildQuery = 'UPDATE user SET '; foreach($_POST as $key => $values) { if($values != '') { $buildQuery .= "{$key} = ? "; // Bind values $paramList .= "{$values},"; } } $buildQuery .= "WHERE userid = '".$user_data['userid']."'"; //remove last comma trim($paramList, ',');

我没有测试过这个，但是像这样的东西应该可以。例如，我没有检查未定义的变量…
使用
if（isset（$\u POST）&&$\u POST！='''{your update code here}
…我有它，这不是问题，问题在update函数中，即使没有发布，它也会更新为“”（空）。嗨，我对mysql查询的I'v编辑我的问题没有那么强，你能看看你的意思吗？谢谢