Php httppost Android，值不会传递到数据库以创建用户

我已经成功地使用httppost从javaandroid代码通过php到mysql创建了一个身份验证。但是，我在创建新用户时遇到问题。我已经检查了其他用户的多篇帖子，我认为它看起来不错。此外，我还创建了一个简单的html表单来测试新用户的php创建，这也很有效

如有任何想法，将不胜感激。下面是我的java代码和PHP。谢谢

    try {
            // create new array list
            nameValuePairs = new ArrayList<NameValuePair>();

            // place them in an array list
            nameValuePairs.add(new BasicNameValuePair("username", user));
            nameValuePairs.add(new BasicNameValuePair("password", pass));

            // add array list to http post
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            // assign executed form container to response
            response = httpclient.execute(httppost);

            // check status code,
            if (response.getStatusLine().getStatusCode() == 200) {
                // assign response entity to htpp entitiy
                entity = response.getEntity();

                // chekc if entity is not null
                if (entity != null) {

                    Log.i("RESPONSE",EntityUtils.toString(entity));

                    Intent intent = new Intent(CreateAccount.this,
                            MainActivity.class);
                    startActivity(intent);

                    // }

                    // display a taost saying login was a success
                    Toast.makeText(CreateAccount.this, user,
                            Toast.LENGTH_SHORT).show();
                    // }

                }
            }
        } catch (Exception e) {
            e.printStackTrace();
            // display toast when there is a connection error
            Toast.makeText(getBaseContext(), "ConnectionError",
                    Toast.LENGTH_SHORT).show();
        }

---

发布时，值被称为“用户名”和“密码”，而服务器检查“用户”和“通过”。你必须使用相同的钥匙

    //get form data

$user = mysql_real_escape_string($_POST['user']);

$pass = mysql_real_escape_string($_POST['pass']);

echo "INSERT INTO androidlogin (user, pass) VALUES ('$user','$pass')";

//insert data
$insert = mysql_query("INSERT INTO androidlogin (user, pass) VALUES  ('$user','$pass')");
if($insert){
$arr2 = array("user" => $user, "pass" => $pass);
echo json_encode($arr2);

}