如何使用JSON（PHP）获取不同的列？

我对PHP非常陌生，甚至不懂JSON。而且，我不知道如何在问题中表达它。我的问题是,

我需要用PHP和数据库中的数据制作一个JSON数据。因此，我的预期输出是什么样的

{ "canFireAPICalls": true, "ads": { "servers": [ { "type": "OpenX", "apiAddress": "http://openx.openvideoads.org/openx/www/delivery/fc.php", } ], "schedule": [ { "zone": "5", "position": "pre-roll" }, { "zone": "33", "width": 450, "height": 50, "startTime": "00:00:05", "duration": "15" } ], } }

我用PHP写的是

while ($doZones->fetch() && $row = $doZones->toArray()) {
    $row_array['zone'] = $row['zoneid'];
    $row_array['position'] = $row['delivery'];

    if($row['delivery'] == 0 || $row['delivery'] == 1 || $row['delivery'] == 4 ){
        $row_array['width'] = $row['width'];
        $row_array['height'] = $row['height'];
    }


    array_push($return_arr,$row_array);
}

$resultJSON .=json_encode($return_arr);

我的输出是

{ "canFireAPICalls": true, "ads": { "servers": [ { "type": "OpenX", "apiAddress": "http://openx.openvideoads.org/openx/www/delivery/fc.php", } ], "schedule":[{"zone":"3","position":"6"},{"zone":"2","position":"6"},{"zone":"4","position":"6"},{"zone":"5","position":"6"},{"zone":"6","position":"1","width":"468","height":"60"},{"zone":"7","position":"6","width":"468","height":"60"},{"zone":"8","position":"0","width":"120","height":"600"},{"zone":"9","position":"7","width":"120","height":"600"},{"zone":"10","position":"0","width":"120","height":"600"},{"zone":"11","position":"0","width":"728","height":"90"},{"zone":"12","position":"0","width":"120","height":"90"},{"zone":"13","position":"1","width":"468","height":"60"},{"zone":"14","position":"3","width":"468","height":"60"},{"zone":"15","position":"1","width":"560","height":"40"},{"zone":"16","position":"4","width":"468","height":"60"},{"zone":"17","position":"6","width":"468","height":"60"},{"zone":"18","position":"6","width":"468","height":"60"},{"zone":"19","position":"7","width":"468","height":"60"}] } }

---

如果你注意到，即使没有宽度和高度，也有。我只想要$row['delivery']为0,1或4时的宽度和高度。但是，一旦找到值0、1或4，即使下一行不是0、1或4，它也会打印宽度和高度。有办法解决这个问题吗？我不知道任何JSON，只是从PHP开始。现在，我不关心缺少的标签，比如持续时间或写预卷。我将在修复此问题后处理它们。

问题出在您的php中。您不会重置数组的值，因此第一次该条件为真时，高度和宽度的值将保留在数组中

您可以通过以下方式进行修复：

while ($doZones->fetch() && $row = $doZones->toArray()) {
    $row_array['zone'] = $row['zoneid'];
    $row_array['position'] = $row['delivery'];

    if($row['delivery'] == 0 || $row['delivery'] == 1 || $row['delivery'] == 4 ){
        $row_array['width'] = $row['width'];
        $row_array['height'] = $row['height'];
    }


    array_push($return_arr,$row_array);
    // Add this line to reset the array and reset width / height
    $row_array = array();
}

$resultJSON .=json_encode($return_arr);

---

这与JSON无关，请确保将正确的数据输入到

$return\u arr

；i、 e使用

print\r（$return\u arr）

并查看其中的内容您可以在内置php函数中使用

json\u encode（$array）

和

json\u decode（$value）

非常感谢，我不知道我应该这么做。我会在50秒内接受你的回答