在PHP中导入Javascript

我有以下HTML和Javascript：

<noscript>
    <div id="player">
    <h2>Warning! You should enable your JavaScript!</h2>
    </div>
</noscript>
<script type="text/javascript">
    var videoSource="<?php echo $fileName;?>";
    createPlayer(videoSource);
</script>

我需要在if中导入此代码块：

<?php
 if($media[$id] != null){
        $video = $media[$id];
        $fileName = "folder/".$video;
       //Here
    }else{
        echo("Error !");
    }
?>

---

这应该满足您的要求：

<?php
 if($media[$id] != null){
        $video = $media[$id];
        $fileName = "folder/".$video;
?>
  ... html ...
<?
    }else{
        echo("Error !");
    }
?>

---

您可以轻松地关闭php标记，插入html代码，然后重新打开php标记，如下所示：

<?php
if($media[$id] != null){
    $video = $media[$id];
    $fileName = "folder/".$video;
?>
<noscript>
    <div id="player">
        <h2>Warning! You should enable your JavaScript!</h2>
    </div>
</noscript>
<script type="text/javascript">
    var videoSource="<?php echo $fileName;?>";
    createPlayer(videoSource);
</script>
<?php
    }else{
        echo("Error !");
    }
?>

用？>包装您的javascript，希望已启用-

<?php
 if($media[$id] != null){
        $video = $media[$id];
        $fileName = "folder/".$video;
?>
<noscript>
    <div id="player">
    <h2>Warning! You should enable your JavaScript!</h2>
    </div>
</noscript>
<script type="text/javascript">
    var videoSource="<?php echo $fileName;?>";
    createPlayer(videoSource);
</script>
<?php
    }else{
        echo("Error !");
    }
?>