Php Laravel 5迁移标识符名称太长

我正在尝试运行以下迁移：

public function up()
{
    Schema::create('lifestyle_questions', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('question');
        $table->timestamps();
    });

    Schema::create('lifestyle_question_answers', function(Blueprint $table)
    {
        $table->increments('id');
        $table->integer('lifestyle_question_id')->unsigned();
        $table->foreign('lifestyle_question_id')->references('id')->on('lifestyle_questions');
        $table->string('answer');
        $table->timestamps();
    });

    Schema::create('user_lifestyle_question_answers', function(Blueprint $table)
    {
        $table->integer('user_id')->unsigned();
        $table->foreign('user_id')->references('id')->on('users');
        $table->integer('lifestyle_question_answer_id')->unsigned();
        $table->foreign('lifestyle_question_answer_id')->references('id')->on('lifestyle_question_answers');
    });
}

但我得到了以下错误：

[Illuminate\Database\QueryException]
SQLSTATE[42000]: Syntax error or access violation: 1059 Identifier name 'user_lifestyle_question_answers_lifestyle_question_answer_id_foreign' is too long (SQL: alter table `user_lifestyle_question_answers` add constraint user_lifestyle_question_answers_lifestyle_question_answer_id_foreign foreign key (`lifestyle_question_answer_id`) references `lifestyle_question_answers` (`id`))

[PDOException]
SQLSTATE[42000]: Syntax error or access violation: 1059 Identifier name 'user_lifestyle_question_answers_lifestyle_question_answer_id_foreign' is too long

---

可以将自定义索引名作为第二个参数传递给foreign（）方法。或者只使用较短的表/列名

所以你想做一些类似的事情：

public function up()
{
    Schema::create('lifestyle_questions', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('question');
        $table->timestamps();
    });

    Schema::create('lifestyle_question_answers', function(Blueprint $table)
    {
        $table->increments('id');
        $table->integer('lifestyle_question_id')->unsigned();
        $table->foreign('lifestyle_question_id', 'lq_id_foreign')->references('id')->on('lifestyle_questions');
        $table->string('answer');
        $table->timestamps();
    });

    Schema::create('user_lifestyle_question_answers', function(Blueprint $table)
    {
        $table->integer('user_id')->unsigned();
        $table->foreign('user_id')->references('id')->on('users');
        $table->integer('lifestyle_question_answer_id')->unsigned();
        $table->foreign('lifestyle_question_answer_id', 'lqa_id_foreign')->references('id')->on('lifestyle_question_answers');
    });
}

---

仅供参考：MySQL标识符应始终少于64个字符。不幸的是，此解决方案在生成复合键时不适用于

primary（）

method:

$table->primary（['id1'，'id']，'custom_index'）

如何解决这个问题？对于那些在生成@Dong3000这样的复合键时遇到这个问题的人，请参见：对于使用

foreignd

的人，您可以这样使用它：

$table->foreignd（'really_long\u foreign\u key\id'）->constrated（）->index（'short\id\u foreign'）